To determine the electrons gained in this redox reaction, we must balance the charges on the side containing the reduced substance and the side with oxidized substance. In this case, the reduced substance is Pb2+ and the oxidized substance is Cr. In each side, 6 electrons are gained or lose to balance the charges. The answer is 6 electrons.
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Answer:</h3>
Partial pressure of He(P(He) = 1.5 atm.
Partial pressure of Ne(P(Ne) = 1 atm.
Partial pressure of Ar(P(Ar) = 0.5 atm.
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Explanation:</h3>
According to Dalton law of partial pressure the sum of partial pressures of individual gases in a gaseous mixture is equivalent to the total pressure.
The partial pressure of a gas in a gaseous mixture is given by the product of the mole fraction and the total pressure.
Our gaseous mixture contains He, Ne, and Ar and the total pressure is 3 atm.
Since we are given the ratios of the gases in the mixture, we can calculate the partial pressure of each gas.
P(He) = 3/6 × 3 atm.
= 1.5 atm.
P(Ne) = 2/6 × 3 atm.
= 1 atm
P(Ar) = 1/6 × 3 atm.
= 0.5 atm
Therefore, the partial pressures of gases He, Ne and Ar are 1.5 atm, 1 atm, and 0.5 atm respectively.
Answer:
yes
Explanation:
because chemical wheathering could wheather it away into a ditch
Answer: C. Electrons are exchanged
Explanation:
Oxidation-Reduction reaction (Redox) is a type of chemical reaction in which there is a transfer of electrons between the reacting substance.
In this type of reaction, one of the reacting substance, called the Reducing Agent, undergoes Oxidation (loss of electrons), while the other reacting substance, called the Oxidising Agent ,undergoes Reduction (gains electron).
The given condition is STP, under this condition, gas has a rule of 22.4 L per mole. And the given equation is already balanced. The ratio of mole number is the same as the ratio of the volume and is also the same as the ratio of coefficients. So the answer is 4.0 liters.
