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AnnZ [28]
3 years ago
12

Find the value of the variable

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

9514 1404 393

Answer:

  y = 12

Step-by-step explanation:

The angle bisector divides the sides of the triangle proportionally. This tells us ...

  y/6 = 8/4

  y = 6(2) . . . . . multiply by 6

  y = 12

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Problem 3
Murljashka [212]

Answer:

-\frac{2}{5}

Step-by-step explanation:

Given expression:

           2x + 5y = -10

The equation of a straight line is;

            y = mx + c

y and x are the coordinates

m is the slope

c is the intercept

 Now;

          let us write the given expression in slope intercept format;

            2x + 5y  = -10

                    5y = -2x - 10

                     y = -\frac{2x}{5}  - 2

So, the slope of the line is -\frac{2}{5}

8 0
2 years ago
The function f(x)=x^2 is graphed on the coordinate grid.
Aleksandr [31]
<h3>Answer:</h3>
  • graphed below.
<h3>Explanation:</h3>
  • vertex: (0, 0)

other points:

<u>x    y</u>

-2  12

-1   3

0   0

1    3

2   12

7 0
2 years ago
Read 2 more answers
The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

6 0
2 years ago
Read 2 more answers
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
What is the decimal form of 63/100
finlep [7]

Answer:

0.63

Step-by-step explanation:

63 divided by 100 on a calculator would get you the answer.

8 0
3 years ago
Read 2 more answers
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