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3 years ago

Find the value of the variable

Mathematics

1 answer:

ElenaW [278]3 years ago

8 0

9514 1404 393

Answer:

y = 12

Step-by-step explanation:

The angle bisector divides the sides of the triangle proportionally. This tells us ...

y/6 = 8/4

y = 6(2) . . . . . multiply by 6

y = 12

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Problem 3

Murljashka [212]

Answer:

$-\frac{2}{5}$

Step-by-step explanation:

Given expression:

2x + 5y = -10

The equation of a straight line is;

y = mx + c

y and x are the coordinates

m is the slope

c is the intercept

Now;

let us write the given expression in slope intercept format;

2x + 5y = -10

5y = -2x - 10

y = $-\frac{2x}{5}$ - 2

So, the slope of the line is $-\frac{2}{5}$

8 0

2 years ago

The function f(x)=x^2 is graphed on the coordinate grid.

Aleksandr [31]

<h3>Answer:</h3>

graphed below.

<h3>Explanation:</h3>

vertex: (0, 0)

other points:

-2 12

-1 3

0 0

1 3

2 12

7 0

2 years ago

Read 2 more answers

The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?

Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

$\sf \: x + x + 1 + x + 2 + x + 3 = 18$

$\sf \: 4x + 1 + 2 + 3 = 18$

$\sf4x + 6 = 18$

$\sf4x = 18 - 6$

$\sf4x = 12$

$\boxed{ \mathfrak{x = 3}}$

1st number = x = 3
2nd number = x+1 = 3+1 = 4
3rd number = x+2 = 3+2 = 5
4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

6 0

2 years ago

Read 2 more answers

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago

What is the decimal form of 63/100

finlep [7]

Answer:

0.63

Step-by-step explanation:

63 divided by 100 on a calculator would get you the answer.

8 0

3 years ago

Read 2 more answers