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2 years ago

Levi was designing a kite. He needs to find the measure of

Mathematics

2 answers:

AleksandrR [38]2 years ago

7 0

So, do you need help finding the measure of the kite?

balandron [24]2 years ago

7 0

Just so you know, there is no picture. Because of that, we cannot answer the question.

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(3x2-10x+4)+(10x-5x+8)

Luba_88 [7]

Answer:

13x^2 - 15x + 12

Step-by-step explanation:

Add like terms.

3x^2 + 10x^2 = 13x^2

-10x + -5x = -15x

4 + 8 = 12

8 0

3 years ago

QUESTION 10

FromTheMoon [43]

conducting the survey as visitors leave the park

The park manager wants to figure out how people like the park so she will conduct the survey as people leave the park.

5 0

3 years ago

Express these numbers in standard form (a)5730(b)0.23(c)0.000231(d)7150000(e)500.8

alisha [4.7K]

Answer:

5730 = 5.73×10³

0.23 = 2.3×10‐¹

0.000231 = 2.31×10-⁴

7150000 = 7.15×10⁶

500.8 = 5.008×10²

8 0

3 years ago

In Northern Yellowstone Lake, earthquakes occur at a mean rate of 1.3 quakes per year. Let X be the number of quakes in a given

hichkok12 [17]

Answer:

a) Earthquakes are random and independent events.

b) There is an 85.71% probability of fewer than three quakes.

c) There is a 0.51% probability of more than five quakes.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

In Northern Yellowstone Lake, earthquakes occur at a mean rate of 1.3 quakes per year, so $\mu = 1.3$

(a) Justify the use of the Poisson model.

Earthquakes are random and independent events.

You can't predict when a earthquake is going to happen, or how many are going to have in a year. It is an estimative.

(b) What is the probability of fewer than three quakes?

This is $P(X < 3)$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.3}*1.3^{0}}{(0)!} = 0.2725$

$P(X = 1) = \frac{e^{-1.3}*1.3^{1}}{(1)!} = 0.3543$

$P(X = 2) = \frac{e^{-1.3}*1.3^{2}}{(2)!} = 0.2303$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2725 + 0.3543 + 0.2303 = 0.8571$

There is an 85.71% probability of fewer than three quakes.

(c) What is the probability of more than five quakes?

This is $P(X > 5)$

We know that either there are 5 or less earthquakes, or there are more than 5 earthquakes. The sum of the probabilities of these events is decimal 1.

$P(X \leq 5) + P(X > 5) = 1$

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.3}*1.3^{0}}{(0)!} = 0.2725$

$P(X = 1) = \frac{e^{-1.3}*1.3^{1}}{(1)!} = 0.3543$

$P(X = 2) = \frac{e^{-1.3}*1.3^{2}}{(2)!} = 0.2303$

$P(X = 3) = \frac{e^{-1.3}*1.3^{3}}{(3)!} = 0.0980$

$P(X = 4) = \frac{e^{-1.3}*1.3^{4}}{(4)!} = 0.0324$

$P(X = 5) = \frac{e^{-1.3}*1.3^{5}}{(5)!} = 0.0084$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.2725 + 0.3543 + 0.2303 + 0.0980 + 0.0324 + 0.0084 = 0.9949$

Finally

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9949 = 0.0051$

There is a 0.51% probability of more than five quakes.

5 0

3 years ago

Aiden works at a garden center where he pots plants. It takes him 2 1/2 hours to pot 15 plants. How many plants can Aiden pot in

Troyanec [42]

Answer:

$6\ plants$

Step-by-step explanation:

Remember that

$2\frac{1}{2}\ hours=\frac{5}{2}\ hours$

Using proportion

$\frac{15}{(5/2)}\frac{plants}{hours} =\frac{x}{1}\frac{plants}{hour}\\ \\x=15*2/5\\ \\x=6\ plants$

8 0

3 years ago