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djyliett [7]
3 years ago
10

PLS HELP ME THIS IS DUE IN A FEW HOURS(i need a graph too pls)

Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

Yes, the total cost of Lacey lesson is a split function of hours scheduled

Step-by-step explanation:

The amount Lacey pays for each hour of golf = $15

The amount Lacey pays for equipment rental = $10

The amount Lacy pays for equipment rental for a 3 hours long lesson = $5

Therefore, we have

Let C represent the total cost of Lacey lesson and let t represent the number of hours, we have;

C = $10 + t × $15 for 0 ≤ t ≤ 3

C = $5 + t × $15 for t > 3

Therefore, the total cost of Lacey lesson is a split function of hours scheduled

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I Need The Answer Plz!!! Geometry Is Hard!!!
Scorpion4ik [409]

Answer:

B. 10

Step-by-step explanation:

First, we need to recognize that the two triangles are similar (the triangle with a leg value of 21 and the triangle with a leg value of 4 and hypotenuse x)

Let's first label the leg of the second triangle as y.

Then, we can set up this equation

\frac{21}{y} =\frac{y}{4}

Cross multiplying gives us

84=y^2

So, y=sqrt(84) or 2 sqrt(21).

Now, using the pythagorean theorem, we get

4^2+2sqrt(21)^2=x^2

100=x^2

x=10

4 0
3 years ago
How do you find the area of the missing side
Margaret [11]

Lets use a rectangle as the example because I dont know what kind of shape you're looking for.

Area of a rectangle = length * width

Length (l) = 62

Width (w) = x

Area = 744

744 = 62 * x

Divide both sides by 62

744/62 = 12

12 = x

That means the width would equal 12

12 * 62 = 744

5 0
2 years ago
Please Help! 20 Points!
iVinArrow [24]
\text {x - coordinate = }  \bigg( 5\dfrac{1}{2}  +  3\dfrac{3}{4} \bigg) \div 2

\text {x - coordinate = }  \bigg( 5\dfrac{2}{4}  +  3\dfrac{3}{4} \bigg) \div 2

\text {x - coordinate = } 8\dfrac{5}{4}   \div 2

\text {x - coordinate = }\dfrac{37}{4}   \times  \dfrac{1}{2}

\text {x - coordinate = }\dfrac{37}{8}

\text {x - coordinate = } 4\dfrac{5}{8}



\text {y - coordinate = } \bigg( -4\dfrac{1}{4} - 1\dfrac{1}{4} \bigg) \div 2

\text {y - coordinate = } -5\dfrac{2}{4} \div 2

\text {y - coordinate = } -\dfrac{22}{4} \times  \dfrac{1}{2}

\text {y - coordinate = } -\dfrac{11}{4}}

\text {y - coordinate = } -2\dfrac{3}{4}}



\text {The coordinate is }\bigg( 4\dfrac{5}{8}, -2\dfrac{3}{4}} \bigg)

6 0
3 years ago
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

5 0
3 years ago
Mrs. McClure's famous peanut butter cookies call for 1 cup of peanut butter for every 1 2 of a cup of oil. Today, she wants to m
bezimeni [28]

Answer:

Amount of butter need for 1 cup of oil = 2 cup of butter

Step-by-step explanation:

Given:

Amount of butter need for 1/2 cup of oil = 1 cup

Find:

Amount of butter need for 1 cup of oil

Computation:

Amount of butter need for 1/2 cup of oil = 1 cup

1 cup butter = 1/2 cup oil

So,

Amount of butter need for 1 cup of oil = 1 / [1/2]

Amount of butter need for 1 cup of oil = 1 / [0.5]

Amount of butter need for 1 cup of oil = 2 cup of butter

6 0
3 years ago
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