This DE has characteristic equation
with a repeated root at r = 3/2. Then the characteristic solution is
which has derivative
Use the given initial conditions to solve for the constants:
and so the particular solution to the IVP is
SOLUTION:
To begin with, let's establish that the formula of this line is in slope-intercept form as follows:
y = mx
The formula for this line isn't:
y = mx + b
This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:
y = mx + b
y = mx + 0
y = mx
Moving on, for ( m ), we need to find the gradient of the line as displayed below:
m = gradient
m = rise / run
m = 10 / 2
m = 5
Now, we must simply substitue ( m ) into the formula in order to obtain the equation for this line as displayed below:
y = mx
y = 5x
Therefore, the answer is:
A. y = 5x
Answer:
1
Step-by-step explanation:
2^−1 + 2^−1
2x2^-1
1
Answer 2.8
Step-by-step explanation:
yeah
Answer:
16 ft
Step-by-step explanation:
Based on the situation above, it forms into a right triangle. Therefore we can apply the Pythagorean Theorem. We will use the formula below:
c = √( a² + b²)
In the problem above, the ladder acts as the hypotenuse denoted by c. It has a length of 20 ft. While the base denoted by b is 12 ft. Therefore, we need to solve for a. We will derive the formula above.
c² = a² + b²
a² = c² - b²
a = √( c² - b² )
a = √( 20² - 12² )
a = 16
The unit is in ft.
Correct me if I'm wrong. I hope it helps.
