Question

A circular loop of wire having a radius of 5.58 cm carries a current of 0.230 A. A vector of unit length and parallel to the dipole moment of the loop is given by 0.60 – 0.80. If the loop is located in a uniform magnetic field given by = (0.140 T) + (0.109 T), find (a) the x-component, (b) the y-component, and (c) the z-component of the torque on the loop and (d) the magnetic potential energy of the

Answer 1

Answer:

see explanation

Explanation:

Given quantities:

radius = r = 0.0558 [m]

current = I = 0.23 [A]

$\vec{B} =$

Now we solve this by obtaining the torque acting on the dipole

$\tau = M \times B$

We obtain the magnetic moment vector M, first, |M| is defined as $M = IA$, where A is the cross-section area of the loop which is $A = \pi r^2=\pi (0.0558)^2= 0.00978 [m^2]$ then

$|M| = 0.23*0.00978 = 0.00225 [A/m^2]$

now the magnetic moment vector is equal to the magnetic dipole moment vector multiplied the magnitude we just obtained  $\vec{M} = M \hat M$

$= 0.00225 *$

Now:

a ) $\tau = M \times B$

b) $U = -M \cdot B$

a) the determinant gives us:

b) the dot product gives = $-1*-7.2*10^{-6} = 7.2*10^{-6}[J]$