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MrRissso [65]
3 years ago
13

In order to go in a circle at a constant speed an object needs

Physics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

So for an object moving in a circle, there must be an inward force acting upon it in order to cause its inward acceleration. This is sometimes referred to as the centripetal force requirement. The word centripetal (not to be confused with the F-word centrifugal) means center seeking.

Explanation:

hope this helps

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Two beams of coherent light are shining on the same sheet of white paper. when referring to the crests and troughs of such waves
tensa zangetsu [6.8K]
Middle of the paper
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4 years ago
When two or more forces act on an object at the same time what are they called
Vilka [71]

Unbalanced forces is what they are called

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3 years ago
What is the dangerous component of a live electrical circuits
mojhsa [17]

The bare wires that have electricity flowing through them that could kill or seriously injure a person.

7 0
4 years ago
Heights of men on a baseball team have a​ bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm
kaheart [24]

Answer:

95 %

99.7 %

Explanation:

\mu = 166 cm = Mean

\sigma = 5 cm =  Standard deviation

a) 156 cm and 176 cm

166-5\times 2=156

166+5\times 2=176

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

166-5\times 3 =151

166+5\times 3=181

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

3 0
3 years ago
A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and
viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, m=5\ g=5\times 10^{-3}\ kg

Hanged mass in the string, m'=200\ g=0.2\ kg

1. The tension in the string is given by :

T=m'g

T=0.2\times 9.8

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

v=\sqrt{\dfrac{T}{M}}

m = M/l

v=\sqrt{\dfrac{Tl}{m}}

v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}

v = 28 m/s

Hence, this is the required solution.

4 0
3 years ago
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