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2 years ago

12

Identify the population and the sample in the situation below:

1 answer:

sladkih [1.3K]2 years ago

3 0

Answer:

your answer is, A Population: soccer team, Sample: starting eleven player.

Step-by-step explanation:

I just took the test.

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Helllohello help please if you want -

Harrizon [31]

Answer:

y = 10 is the true number sequence

Step-by-step explanation:

y + 6 = 16

y = 16 - 6

y = 10

6 0

2 years ago

Ten is at least the product of a number h and 5

slamgirl [31]

When you hear the word 'product' in mathematics, it means that you're multiplying something. In this case, it's h * 5. When it says 'at least', this means that ten is the smallest possible answer, or in other words, h*5 is greater than or equal to 10.

$h * 5$ ≥ $10$

7 0

2 years ago

Read 2 more answers

At Scobee Middle School, 35% of the seventh graders ride the bus to school. If there are 320 seventh graders, how many 7th grade

anzhelika [568]

Answer: 112 7th graders ride the bus .

Step-by-step explanation:

Given: The proportion of 7th graders ride the bus to school= 35% = 0.35 [to remove % we divide number by 100]

If there are 320 seventh graders, then the number of 7th graders ride the bus = 320 x (proportion of 7th graders ride the bus to school)

$0.35 \times 320$

$= 112$

Hence, 112 7th graders ride the bus .

6 0

2 years ago

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

2 years ago

The image shows parallel lines cut by a transversal. The expressions represent unknown angle measurements. What is the value of

Triss [41]

Answer) C. 77
This picture shows how I got to the answer. You must set up the two expressions to equal each other and then solve for X

7 0

3 years ago