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Volgvan
3 years ago
14

Help me i need the answer

Mathematics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

its red

0\leqy\leq225

Step-by-step explanation:

Inessa05 [86]3 years ago
4 0
The answer is red !!
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Please help fast will give brainliest
MrRa [10]

Answer:

MN = 160

Step-by-step explanation:

We know that arc MN = arc NO

17g - 10 = 14g+ 20

Subtract 14g from each side

3g -10 = 14g-14g+20

3g -10 =20

Add 10 to each side

3g = 20+10

3g = 30

Divide by 3

3g/3= 30/3

g= 10

We want the arc MN

17g - 10

17(10) - 10

170 -10

160

5 0
3 years ago
What does the point (2,24) represent?
almond37 [142]

Answer:

not sure what you mean here but..... 2 represents your x value which will go on the x intercept. And 24 represents your y value. When you have both of these values, you can plot it on a coordinate graph.


4 0
3 years ago
It is the morning of the sandcastle-building competition at the beach. Dory has been looking forward to this event for months. A
zvonat [6]
One way is by comparing the weather for today as compared to the rest of the week or month.

6 0
3 years ago
Read 2 more answers
What is an equation that passes through (18,2) and is parallel to 3y-x=-12
MrRa [10]
3(2)-18=-12
6-18 = -12
-12 = -12
5 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
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