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3 years ago

Not really sure how to do this with a negative number

Mathematics

2 answers:

Umnica [9.8K]3 years ago

5 0

Note that (-1/7) = -(1/7).

So you have

1 -1 -1
--- * ------ = ------
2 7 14

Oksi-84 [34.3K]3 years ago

4 0

1/2*(-1/7) = - (1*1)/(2*7)= - 1/14

(+)*(-) = (-)

Answer : - 1/14

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The cube of the difference of a number and 4

lbvjy [14]

Answer:

(x - 4)³

Step-by-step explanation:

"The cube of x" would be x³. The difference of a number and 4 would be x - 4.

Therefore, "the cube of the difference of a number and 4" would be

(x - 4)³

6 0

3 years ago

A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple

devlian [24]

Answer:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=46$ represent the mean height for the sample

$s=5.148$ represent the sample standard deviation

$n=5$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:

Null hypothesis: $\mu = 40$

Alternative hypothesis: $\mu \neq 40$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0

3 years ago

When would u need an interpreter? What would that person do?

seropon [69]

If you speak a different language this person can interpret your speaking into the language understandable by the other party

6 0

3 years ago

Read 2 more answers

A salesman earning $9.50 per hour receives a 12% raise. To find the new wage, multiply $9.50 by 0.12 and add the result to $9.50

avanturin [10]

I believe you would be correct. :)

5 0

3 years ago

Read 2 more answers

statuscvo [17]

Part A)

His sample only involves days during the summer (if Devin is in the northern hemisphere), which would mean that the high temperatures he'll record are likely to be higher than the average. Therefore, the sample mean he computes does not represent the average high temperature for the whole year.

----------------------------------------

Part B)

To correct his mistake, he needs to sample every day of the year. Or he could sample a few days of each month (say the first ten days of each month). That way the entire year is better represented. The other seasons of spring, fall and winter are included now.

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3 years ago