Let's set up two equations:
x+y=20 We know she brought total of 20, some of each so x=small y=big
20x+ 30y=450
x+y= 20
-y -y
------------
x= 20 -y
substitute into the other equation:
20 (20-y) + 30y = 450
400 - 20y + 30y = 450
400+ 10 y = 450
10 y = 50
y= 5
So she brought 5 big cases. Then substitute the value of y into one of the equations.
5+ x = 20
x= 15
So we bought 15 small cases and 5 big cases.
Hope this helps! Please give me the brainliest answer if you like it! If you have further questions, please leave a comment or add me as a friend!
Answer:
The price with 8% sales tax is $691.20
not for sure if its right
Step-by-step explanation:
Answer:
96 and 288
Step-by-step explanation:
So, we need to find 2 numbers such that their sum is 8 and they do not have common factor (Relatively prime). Both these numbers will be divisible by 48 but there would be no other common divisor (after dividing by 48).
Such order independent pairs are (1,7) and (3,5).
Difference between them would be (7–1)*48=6*48 and (5–3)*48=2*48 respectively.
The differences are 6*48=288 and 2*48=96.
We have found difference without finding numbers.
Ans.: 96 and 288
p.s.: The number pairs (again order neutral) would be (48, 336) and (144, 240)
Difference for 48 and 336 add up to 384, their HCF is 48. These two numbers match the conditions. Their difference is 288.
Difference of 144 and 240 add up to 384, their HFC is 48 (the numbers are 48*3 and 48*5, common factor is 48 and no other common factor for 3 and 5; 48 is HCF). The difference is 96.
