To do this, first, find the decimal of 1/3. You will divide 1 by 3. This equals .333333333(goes on forever). Put a repeating bar over the first 3 to show that it goes on forever (put this: - over the .3) Now divide to find out how much you will need to subtract by. 960*33.3(with - over .3)=28.8. Subtract 28.8 from 960 (960-28.8=931.2) 931.2 is the answer.
Answer:6.5
To find the mean (average)
Add 3.5 and 9.5 which equals 13. Then you divide 13 by 2 because you added two numbers (3.5 and 9.5) which equals 6.5.
S= a(1-r ⁿ) /(1-r) & when r is < 1 & n →∞, the sum becomes S= a/(1-r)
Progression P is 2,1, 1/2,1/4,.. ==> r = 1/2
Sum of P when n--> ∞ = 2/(1-1/2) ==> S =4
Progression Q is 3,1,1/3,1/9,....==> r = 1/3
Sum of Q when n--> ∞ = 3/(1-1/3) ==> S =4.5
GIVEN THAT 4, 9/2 & X (to be calculated later is a geometric Progression, hence 9/2 - 4 = 0.5 =d (common difference , so X = 4.5+0.5 & X = 5
Sum of R =5 Then => 5= 4 /(1-r) & r=1/5
Then the sum of R = 4/(1-1/5) ==> S of R =5
If 500 high school students, 376 said they would prefer to have computers in every classroom then the confidence interval at 95% is (71.41%,78.99%) Since option (a) is correct.
Given x= 376, n = 500
The (71.41%,78.99%)
Critical values
Using the z-table the z-critical value at the given significance level at α=0.05 is,
Construct a 95% confidence interval
That is,
= (71.41%,78.99%)
Learn more about confidence intervals here: brainly.com/question/15712887
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Answer:19/26
Step-by-step explanation:
Total number of students=26
Number of students that play basket ball=8
Number of students that play
baseball=11
Probability of playing both=6
Probability of playing either of the 2 games=8/26+11/26=19/26