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Eddi Din [679]
3 years ago
13

Under a certain set of conditions, the percent yield of a reaction that produces carbon dioxide is 75.0%. What mass in grams of

CO2 will actually be recovered if the theoretical yield is 26.7 grams?

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
6 0

Answer:

Actual yield = 20.03g

Explanation:

% yield = 100.\frac{actual yield}{theoretical yield}% yield = 100. \frac{actual \ yield}{theoretical \ yield}

Actual yield = % yield.(theoretical yield) / 100

Actual yield = 75.26.7/100

Actual yield = 20.025

BartSMP [9]3 years ago
3 0

Answer: I got 20.025 and then I rounded it to 20.0

Explanation:

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valentina_108 [34]

Answer:

C ) 2, 1, 2

Explanation:

The given reaction is synthesis reaction in which lithium and bromine react to form lithium bromide.

Chemical equation:

Li + Br₂    →    LiBr

Balanced chemical equation:

2Li + Br₂    →    2LiBr

Step 1:

Li + Br₂    →    LiBr

left hand side                         Right hand side

Li = 1                                        Li = 1

Br = 2                                        Br = 1

Step 2:

Li + Br₂    →    2LiBr

left hand side                         Right hand side

Li = 1                                        Li = 2

Br = 2                                        Br = 2

Step 3:

2Li + Br₂    →    2LiBr

left hand side                         Right hand side

Li = 2                                       Li = 2

Br = 2                                        Br = 2

3 0
3 years ago
A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh
Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

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Answer:

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