According to the law of conservation of mass, what is the same on both sides of a balanced chemical equation?
A. the volume of the substances
B. the subscripts
C. the total mass of atoms
D. the coefficients
Answer:
A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.
Explanation:
Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. ... Use coefficients of products and reactants to balance the number of atoms of an element on both sides of a chemical equation.
Consider the balanced equation for the combustion of methane.
CH
4
+
2O
2
→
CO
2
+
2H
2
O
All balanced chemical equations must have the same number of each type of atom on both sides of the arrow.
In this equation, we have 1
C
atom, 4
H
atoms, and 4
O
atoms on each side of the arrow.
The number of atoms does not change, so the total mass of all the atoms is the same before and after the reaction. Mass is conserved.
Here is a video that discusses the importance of balancing a chemical equation.
Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.
Blood cells, glucose , skin cells and etc .
Answer:
The answer to your question is 0.113 moles of Fe₂O₃
Explanation:
Data
moles of Fe₂O₃ = ?
mass of Fe₂O₃ = 18 grams
Process
1.- Calculate the molar mass of Fe₂O₃
Fe₂O₃ = (56 x 2) + (16 x 3)
= 112 + 48
= 160 g
2.- Use proportions to solve this problem. The molar mass is equivalent to 1 mol.
160 g of Fe₂O₃ --------------- 1 mol
18 g of Fe₂O₃ ---------------- x
x = (18 x 1)/160
x = 0.113 moles of Fe₂O₃
Answer:
80mL
Explanation:
Step 1:
Data obtained from the question.
Initial Volume (V1) = 40mL
Initial temperature (T1) = –123°C
Final temperature (T2) = 27°C
Final volume (V2) =..?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
T(K) = T(°C) + 273
Initial temperature (T1) = –123°C =
–123°C + 273 = 150K
Final temperature (T2) = 27°C = 27°C + 273 = 300K
Step 3:
Determination of the final volume.
This can be obtained as follow:
V1/T1 = V2/T2
Initial Volume (V1) = 40mL
Initial temperature (T1) = 150K
Final temperature (T2) = 300
Final volume (V2) =..?
V1/T1 = V2 /T2
40/150 = V2 /300
Cross multiply
150 x V2 = 40 x 300
Divide both side by 150
V2 = (40 x 300) /150
V2 = 80mL
Therefore, the new volume of the gas is 80mL
