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3 years ago

(y-6x+5)+(6y-5x+3)+(5y+2x-7)

Mathematics

1 answer:

larisa [96]3 years ago

8 0

Answer:

Hi! The answer to your question is -9x+12y+1

Step-by-step explanation:

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Whats the difference in 2/3 - 1/6

nasty-shy [4]

Answer:

2/3&1/6

2/3- 1/6

the LCM for 3 and 6 is 6

=(2x6)/(3x6) -(1x6)/(6x6)

=4/6-1/6

=(4-1)/6

find the difference

= 3/6

=1/2

2/3-1/6= 1/2

By using LCM method, 1/2 is the equivalent fraction by subtracting 1/6 from 2/3.

2/3&1/6

2/3- 1/6

cross multiply

2x6-1x3/3x6

simplify

12-3/18

=9/18

= 1/2

2/3-1/6 = 1/2

By using cross multiplication method, 1/2 is the difference between two fractions 2/3 and 1/6.

Step-by-step explanation:

hope that helps>3

7 0

3 years ago

I need help with questions 10-14, would appreciate work shown

Nana76 [90]

Answer:

Step-by-step explanation:

10-h

11-A

12-g

13-a

14-f

Mark as brainlest please

8 0

3 years ago

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

AnnyKZ [126]

Answer:

A) $5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5}$ (Yes. It has a value between zero and one.)

B) $\frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147$ (No. It does not have a value between zero and one.)

C) $\left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}$ . (Yes. It has a value between zero and one.)

D) $\frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49}$ (Yes. It has a value between zero and one.)