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noname [10]
3 years ago
7

You push a 10 n object 10 m how much work was done on the object​

Engineering
2 answers:
masya89 [10]3 years ago
8 0
W = F D

W = 10N × 10 m

W = 100 N.m

W = 100 J
dezoksy [38]3 years ago
5 0

Answer: the answer is

Work= Force * Distance

Work= 10N * 10m

Work= 100J

Explanation:

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Read 2 more answers
For some metal alloy, a true stress of 415 MPa produces a plastic true strain of 0.475. How much does a specimen of this materia
krok68 [10]

Answer:

58.63\ \text{mm}

Explanation:

\sigma_t = True stress = 415 MPa

\varepsilon_t = True strain = 0.475

l_i = Original length of the alloy = 300 mm

Let us assume n = Strain hardening component = 0.25

K = Constant

True stress is given by

\sigma_t=K(\varepsilon_t)^n\\\Rightarrow K=\dfrac{\sigma_t}{(\varepsilon_t)^n}\\\Rightarrow K=\dfrac{415}{0.475^{0.25}}\\\Rightarrow K=499.89\approx 500\ \text{MPa}

Now \sigma_t=325\ \text{MPa}

325=500(\varepsilon_t)^{0.25}\\\Rightarrow (\dfrac{325}{500})^{\dfrac{1}{0.25}}=(\varepsilon_t)\\\Rightarrow \varepsilon_t=0.1785

True strain is given by

\varepsilon_t=\ln(\dfrac{l_f}{l_i})\\\Rightarrow e^{\varepsilon_t}=\dfrac{l_f}{l_i}\\\Rightarrow l_f=l_ie^{\varepsilon_t}\\\Rightarrow l_f=300e^{0.1785}\\\Rightarrow l_f=358.63\ \text{mm}

Elongation of material is l_f-l_i=358.63-300=58.63\ \text{mm}.

4 0
3 years ago
how can a magnet be used to produce an electric current? a. hold the magnet next to a wire b. connect a wire to each end of the
Dafna11 [192]

Answer:

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