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3 years ago

Are you able to text without looking at your phone?

1 answer:

5 0

Yes.
Yes
Yes, I told them that it was dangerous.
No.
Both are bad but I think driving drunk is way worse. Yes both take your attention away from the road but driving drunk takes your attention away permanently while texting and driving only takes it away for a few minutes.

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Which side of the disc sander do you sand on 1. Right 2. Left 3. Up 4. Down

guapka [62]

$\mathbb \orange{Answer}$

$\mathbb \red{ Left}$

3 0

2 years ago

Calculate the magnitude of the velocity and the θ angular direction of the block and the bullet together when the 50 g bullet mo

almond37 [142]

Answer:

Magnitude of the velocity = 16.82 m/s

Angular direction, θ = 52.41°

Explanation:

As given ,

mass of bullet, m₁= 50g = 0.05 kg

speed of bullet , u₁ = 600 m/s

mass of the block , m₂ = 4 kg

speed of the block before collision , u₂ = 12 m/s

direction , θ = 30°

Now,

Assume that the combined velocity of bullet and block after collision = v

and the direction = θ

Now, from the conservation of momentum in x - direction :

m₁ u₁ + m₂ u₂ = ( m₁ + m₂ ) vₓ

where v = final velocity after collision

u₁ = initial velocity of bullet before collision = 0

m₁ = mass of the bullet before collision = 0.05 kg

u₂ = velocity of block before collision = 12 cos(30° )

m₂ = mass of block before collision

m₁ + m₂ = combined mass of bullet and block after collision = 0.05 + 4

∴ we get

0.05 (0) + 4(12 cos(30° ) ) = ( 0.05 + 4 ) vₓ

⇒ 0 + 4(6√3) = 4.05 vₓ

⇒24√3 = 4.05 vₓ

⇒vₓ = 10.26 m/s

Now, from the conservation of momentum in y - direction :

m₁ u₁ + m₂ u₂ = ( m₁ + m₂ ) $v_{y}$

where v = final velocity after collision

u₁= initial velocity of bullet before collision = 600

m₁ = mass of the bullet before collision = 0.05 kg

u₂ = velocity of block before collision = 12 sin(30° )

m₂= mass of block before collision

m₁+ m₂= combined mass of bullet and block after collision = 0.05 + 4

∴ we get

0.05 (600) + 4(12 sin(30° ) ) = ( 0.05 + 4 ) $v_{y}$

⇒ 30 + 4(6) = 4.05 $v_{y}$

⇒30 +24 = 4.05 $v_{y}$

⇒54 = 4.05 $v_{y}$

⇒ $v_{y}$ = 13.33 m/s

Now, the magnitude of the velocity = √vₓ² + $v_{y}$ ² = √(10.26)² + (13.33)²

= √105.26 + 177.68

= √282.95 = 16.82

The angular direction, θ = $tan^{-1}$ ( $\frac{v_{y} }{v_{x} }$ ) = $tan^{-1}$ ( $\frac{13.33}{10.26}$ ) = $tan^{-1}$ (1.299) = 52.41°

8 0

3 years ago

Pretend 1% of the population has a disease. You have a test that determines if you have that disease, but it’s only 80% accurate

Ghella [55]

Answer:

3.88% of the time

Explanation:

3 0

2 years ago

1. What is resilience engineering and how does it pertain to the current corona virus crisis?

saw5 [17]

Answer:

the ability to absorb or avoid damage without suffering complete failure and is an objective of design, maintenance and restoration for buildings and infrastructure

Explanation:

8 0

3 years ago

Drivers with an average of 20/40 vision travel at 55 mph in the curb lane of a freeway, where exit ramps are designed for 25 mph

Tom [10]

Answer:

The sign board must be placed 573 ft ahead of the exit.

Explanation:

Distance needed for reducing the speed from 55 mph to 25 mph is given as

$d=\frac{v_f^2-v_i^2}{30 \times (\frac{a}{g}-G)}$