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2 years ago

6

The Garcia family drives 3/4 of the distance to their. grandparents house in 3/4 hour. How many hours will it take to drive to t

heir grandparents house at the same rate? A-9/16 B-1. C- 1 7/9

1 answer:

chubhunter [2.5K]2 years ago

8 0

Answer:

B

Step-by-step explanation:

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Eighteen cement squares cover a patio with an area of 40.5m^2. What is the side length of one of the squares

Firlakuza [10]

Idk :) but the other guy answering might be able to help you. please give me a like!

6 0

2 years ago

An equations'system

yaroslaw [1]

$1. \: x = \frac{11}{9} y + \frac{5}{9} \\ x = \frac{5}{6} y + \frac{1}{6} \\ \\ 2. \: x = \frac{3}{2} y + 2 \\ x = \frac{3}{2} y + 2$

3 0

3 years ago

Find the distance between the two points.<br> (-6, – 7), (0,0)

Elden [556K]

Answer:

√85

Step-by-step explanation:

for this, you will probably need to draw a graph. Plot the points, and then you will notice that you can draw a triangle with one side being the x-axis ( go on to (-6,0) then drop down unitll you hit the point (-6;-7)

// use the pythagoream theorem to find the length

the distance of the leg on the x-axis is 6 (calculate 0-(-6))

the distance of the leg that is dropping down is -7 (calculate 0-(-7))

then we have 2 legs and need to find the hypotenuse.

Pythagorean theorem a^2 + b^2 = c^2

substitute :

6^2 + 7^2 = c^2

36+49 = 85

c= √85

8 0

2 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

5 0

3 years ago

The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in

Elanso [62]

Answer:

0 < t < $\frac{5}{3}$

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = $\frac{20}{12}$

t = $\frac{5}{3}$ days

Therefore, there are two intervals in which the given function is defined

(0, $\frac{5}{3}$ ) and ( $\frac{5}{3}$ , ∞)

For the interval (0, $\frac{5}{3}$ ),

p'(1) = 20 - 12(1) = 20

For the interval ( $\frac{5}{3}$ , ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, $\frac{5}{3}$ ) indicates that the function is increasing.

0 < t < $\frac{5}{3}$

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0

2 years ago