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2 years ago

10

the currency in sweden is the kronor. the exchange rate is approximately $1 for every 7 kronor. at this rate, how many dollars w

ould you get if you exchanged 14 kronor?

1 answer:

REY [17]2 years ago

7 0

Answer:

$2

Step-by-step explanation:

If $1 = 7 kronor, 2$ would = 14 kronor

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Please answer this question now

lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2) M (6;2) C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 = (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0

2 years ago

a school had 690 students sign up for the trivia teams if they wanted to have nine teams with the same number of students on eac

uysha [10]

Answer:

3 more students need to sign up

Step-by-step explanation:

Let the equal number of students in 9 teams be x.

Total number of signed up students = 690.

Let t be the required number of students to be signed.

Therefore, 9x = 690+t.

This means, 690+t is a multiple of 9.

The least value of t to make 690+t, a multiple of 9 is 3 and hence,

$\frac{693}{9}$

= 77

Hence, 3 more students need to sign up and each of the 9 teams consists of 77 students.

5 0

2 years ago

What is the answer to <br> 6x> -54

Anestetic [448]

Answer:

6 times whatever x is would be greater that -54

7 0

2 years ago

A low-strength children’s/adult chewable aspirin tablet contains 81 mg of aspirin per tablet. How many tablets may be prepared f

Svetlanka [38]

Answer:

12,345 tablets may be prepared from 1 kg of aspirin.

Step-by-step explanation:

The problem states that low-strength children’s/adult chewable aspirin tablets contains 81 mg of aspirin per tablet. And asks how many tablets may be prepared from 1 kg of aspirin.

Since the problem measures the weight of a tablet in kg, the first step is the conversion of 81mg to kg.

Each kg has 1,000,000mg. So

1kg - 1,000,000mg

xkg - 81mg.

1,000,000x = 81

$x = \frac{81}{1,000,000}$

x = 0.000081kg

Each tablet generally contains 0.000081kg of aspirin. How many such tablets may be prepared from 1 kg of aspirin?

1 tablet - 0.000081kg

x tablets - 1kg

0.000081x = 1

$x = \frac{1}{0.000081}$

x = 12,345 tablets

12,345 tablets may be prepared from 1 kg of aspirin.

4 0

2 years ago

PLEASE HELP ME WITH THIS QUESTION ASAP. please and thank you

kotegsom [21]

To solve the given equation, you would need to multiply t by both terms inside the parenthesis.

The equation would be D. (t*14) - (t*5)

3 0

3 years ago