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zlopas [31]
3 years ago
8

Can someone please help me on this!!

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0
Question ^ is the awnser :) I just checked to make sur e
Svetlanka [38]3 years ago
5 0

Answer:

read.....

Step-by-step explanation:

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Write the output when the input is n input 1 7 8 n output 3 21 24 _
Ugo [173]

Answer:

3n

Step-by-step explanation:

Looking at other pairs, we know that the output is 3 times the input.

So, the output is 3n when the input is n

5 0
4 years ago
A movie theater has a rows and b seats in each row how many seats are in the theater?
astra-53 [7]

Answer:

ab

Step-by-step explanation:


5 0
4 years ago
Read 2 more answers
The vertical height v, in feet, of a snowboarder jumping off of an overhang can be modeled by the function h(t)=15-10t-16t^2, wh
olga55 [171]
I don't know for sure, but I think there might be an error in the way you copied your function. In all of my dealings with these types of problems, I have learned the formula to be h(t) = 15 + 10t - 16t^2. Notice the plus in front of the "10t". This is due to the fact that if he pushes off of the overhang he would have an upward force of 10 feet per second as soon as his feet left the ground. The only thing pulling him back to Earth is gravity, modeled by the "-16t^2". This is derived from a bit of slightly advanced physics involving the gravitational constant, but let's work under my formula for a second...

Either way, we will wind up using the Quadratic Formula (or possibly factoring if the numbers are easy enough to work with). So let's start. 

h(t)= 15 +10t - 16t^2

In order to use the QF or factoring I will need to make h(t)=0. Simply done by:

0= 15 +10t -16t^2

Looking at the numbers, I'd prefer to use the QF so here it is:

x= \frac{-b + or -  \sqrt{b^{2}-4ac } }{2a}

I know that my answer will need to be positive since you can't have a negative value when dealing with time, so I will eliminate the positive sign from the "+or-" part leaving me with:

x= \frac{-b -\sqrt{b^{2}-4ac } }{2a}

And I know that a= -16, b= 10, and c=15. So all that's left to do is substitute and solve.

x= \frac{-10 -\sqrt{-16^{2}-4*-16*15 } }{2*-16} 

There's a decent amount of math that would be difficult and sloppy for me to do over the computer, but all you need to do is solve the rest of the equation and you would get your answer.

Exact answer: \frac{5-4 \sqrt{15} }{8} or rounded answer: ≈1.31 seconds.

Hope this helps!
NoThisIsPatrick

7 0
3 years ago
Read 2 more answers
The roots of the quadratic equation $z^2 + az + b = 0$ are $2 - 3i$ and $2 + 3i$. What is $a+b$?
AlladinOne [14]
We know for our problem that the zeroes of our quadratic equation are (2-3i) and (2+3i), which means that the solutions for our equation are x=2-3i and x=2+3i. We are going to use those solutions to express our quadratic equation in the form a x^{2} +bx+c; to do that we will use the <span>zero factor property in reverse:
</span>x=2-3i
x-2=-3i
x-2+3i=0
<span>
</span>x=2+3i
x-2=3i
x-2-3i=0
<span>
Now, we can multiply the left sides of our equations:
</span>(x-2+3i)(x-2-3i)= x^{2} -2x-3ix-2x+4+6i+3ix-6i-3^2i^2
<span>= </span>x^{2}-4x+4-9i^{2}
= x^{2} -4x+4+9
= x^{2} -4x+13
Now that we have our quadratic in the form a x^{2} +bx+c, we can infer that a=1 and b=-4; therefore, we can conclude that a+b=1+(-4)=1-4=-3.
6 0
4 years ago
There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral
leva [86]

Answer:

The answer is "\sqrt{12.5}"

Step-by-step explanation:

\to (3,2),  \ (6,1)

Distance=\sqrt{9+1}=\sqrt{10}

midpoint height =\sqrt{10+2.5}=\sqrt{12.5}

let

Gradient = \frac{1}{-3}      

Perpendicular Gradient= 3

midpoints = (4.5, 1.5)

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle(4.5,1.5) radius will be\sqrt{12.5}.

5 0
3 years ago
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