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zlopas [31]
3 years ago
8

Can someone please help me on this!!

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0
Question ^ is the awnser :) I just checked to make sur e
Svetlanka [38]3 years ago
5 0

Answer:

read.....

Step-by-step explanation:

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Suppose that 35 people are divided in a random mannerinto two teams in such a way that one team contains10 people and the other
Alisiya [41]

To be precise, the size of your sample space is <span><span>(<span>2410</span>)</span><span>(<span>2410</span>)</span></span>. This number does go on the bottom of the fraction, and what goes on top is the size of the event. Break up the event into independent events 1. choose the 2 defective bulbs, and 2. choose the remaining 8 bulbs. I don't have much choice in event 1. There is only one way to choose both of the defective balls. In other words, <span><span>(<span>22</span>)</span><span>(<span>22</span>)</span></span> (choosing 2 defective bulbs from a set of 2 defective bulbs). For event 2, there are <span><span>24−2=22</span><span>24−2=22</span></span> nondefective bulbs, and I must choose <span>88</span> of them, so that's <span><span>(<span>228</span>)</span><span>(<span>228</span>)</span></span>. Finally, since events 1 and 2 are independent, we multiply the answers for the combined event: <span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span></span>

<span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span></span>

Or, since <span><span><span>(<span>22</span>)</span>=1</span><span><span>(<span>22</span>)</span>=1</span></span>,

<span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span></span>

Hope this helps!

7 0
3 years ago
What are the solutions to the equation?
nekit [7.7K]

The correct answer is -5 and 3

I took the test and this was the correct answer

Hope I helped :)

6 0
3 years ago
Read 2 more answers
Help me solve this please
Anna71 [15]
27+ 2/5×-1/2 = 27 - 1/5
(135 - 1)/5 = 134 /5 <——answer
8 0
2 years ago
What is the x and y intercept of the parabola y=x^2-6x+10 and ow do you graph the equation
Mazyrski [523]
The x- intercept is where y = 0 on the graph and the y- intercept is where x= 0 on the graph. When X=0, all the terms, except for the constant are equal to zero, thus the y- intercept is the constant. y=10 when x=0. Use the quadratic formula to find the x value where y=0. 
x= (-b +or- sqrt(b^2 -4ac))/2a

y=ax^2 +bx +c

The answer for the x- int is imaginary. This happens because 10 is the parabola's minimum value and it never touches the x- axis. y-int is 10
7 0
3 years ago
What is the value of the expression below when x = 5 and y = 2?<br>X + 6y​
Vedmedyk [2.9K]
Instead of X put 5 and instead of y put 2
5+6(2)
5+12= 17
7 0
3 years ago
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