You solve the substitution method to solve a system of equality by expressing one variable in terms of the other using one equation, and then plugging this expression in the other(s).
In this case, the first equation gives us a way to express n in terms of m. So, we can replace every occurrence of n in the second equation with the given formula.
The result is

So, the second equation turned to be an equality, i.e. an equation where both sides are the same.
This implies that the system has infinitely many solutions, because every couple
such that
is a solution to the system, because it satisfies both equations: the first is trivially satisfied, whereas the second is an identity, and as such is satisfied by any value of the variable.
Greetings!
The best way to compare fractions is to find the LCM (The Lowest Common Denominator) of each of the fractions. This can be done simply by listing the multiples of the denominators.
Multiples:
3: 3,6,9,12,15,18,21,24,27...210,213
10:10,20,30,40,60,70,80...210,220
6: 6,12,18,24,30,36,42,48...210,216
7: 7,14,21,28,35,42,49...210,217
The LCM is 210:
3*70=210
10*21=210
6*35=210
7*30=210
Now, we must do what we do the denominators to the numerators:
1*70=70
70/210
2*21=42
42/210
1*35=35
=35/210
2*30=60
=60/210
The fraction with the largest numerator has the greatest value; In this case it 1/3 or 70/210.
Hope this helps.
-Benjamin
Which of the following relations represent a function? A. {(-1,-1),(0,0),(2,2),(5,5)}. B. None of these. C. {(0,3),(0,-3),(-3,0)
Cerrena [4.2K]
Answer:
A
Step-by-step explanation:
In a list of ordered pairs, a relation that is a function will not have any repeated x-values.
A -- a function (x-values are {-1, 0, 2, 5} with no repeats)
B -- irrelevant
C -- not a function (x-values are {0, 0, -3, 3} with 0 being repeated)
D -- not a function (x-values are {-2, -1, -2, 2} with -2 being repeated)
Answer:
100km
Step-by-step explanation: