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sesenic [268]
2 years ago
6

What is the zero of r(x) = 8/3X-16

Mathematics
1 answer:
Masteriza [31]2 years ago
8 0

Answer:

x = 6

Step-by-step explanation:

(8/3)x - 16 = 0

Add 16 to both sides

(8/3)x = 16

Multiply both sides by 3/8

x = 16(3/8)

x = 6

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out of 30 questions on the maths test tomi knew the answer to 27 of them what percentage of questions did tomi know the answer f
Vedmedyk [2.9K]

Answer:

90

Step-by-step explanation:

\frac{27}{30}  \times 100

so after we cut the nessecary we get 90%

Hope this helps you

Mark as the brainlist

thank you

8 0
2 years ago
I can't figure this out and didn't see it on brainly, pls help​
ch4aika [34]

Answer:

it's 8

Step-by-step explanation:

(10×1/5)^3=2^3=8

6 0
2 years ago
Read 2 more answers
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
A box contains 17 balls numbered 1 through 17. Two balls are drawn in succession without replacement. If the second ball has the
Brilliant_brown [7]

Answer:

1 ; 7 /17

Step-by-step explanation:

17 balls numbered 1 through 17

Picking without replacement :

If the second ball picked = 4

P(first ball has a smaller number)

Numbers less Than = (3, 2, 1)

P(number less than second ball Given 4 is drawn for second ball) :

= (3/17 * 1/16) ÷ (3/17 * 1/16) +) 14/17 * 0)

= (3 / 272) / (3 /272) * 0

= 3 / 272 * 272 / 3

= 1

2.)

(8/17 * 7/8) ÷ (8/17 * 7/8) + (9/17 * 1/17)

7/17 ÷ (7 /17) + 10/17

7 /17 ÷ 17/17

7/17 ÷ 1

7 /17

7 0
3 years ago
35) The volume of a cone is 8 cubic
Anuta_ua [19.1K]

Answer:

24 cm³

Step-by-step explanation:

Volume of a cylinder is three times of a cone with same measurements

volume of cone is 8cm³

then,volume of cylinder is 8 × 3 = 24

7 0
1 year ago
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