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podryga [215]
3 years ago
9

HELP PLEASE.

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

B. ∆<em>X</em><em>Y</em><em>Z</em><em>,</em><em> </em>in which <em>m∠X</em> = 10°<em> </em>and<em> </em><em>m∠Z </em>= 25°

Step-by-step explanation:

∆ABC

m∠A = 10°

m∠B = 145°

m∠C = 180° - (m∠A + m∠B )

= 180° - (10° + 145°)

= 180° - 155°

m∠C = 25°

∆XYZ

m∠X = 10°

m∠Z = 25°

m∠Y = 180° - (m∠X + m∠Z)

= 180° - (10° + 25°)

= 180° - 35°

m∠Y = 145°

so,

m∠A = m∠X = 10°

m∠C = m∠Z = 25°

m∠B = m∠Y = 145°

<em>I</em><em>'</em><em>m</em><em> </em><em>j</em><em>u</em><em>s</em><em>t</em><em> </em><em>o</em><em>r</em><em>d</em><em>i</em><em>n</em><em>a</em><em>r</em><em>y</em><em> </em><em>h</em><em>u</em><em>m</em><em>a</em><em>n</em><em>,</em><em> </em>CMIIW

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