<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
192 cm²
<h3>
<u>Step</u><u> </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u></h3>
Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .
<u>According</u><u> to Pythagoras Theorem :- </u>
=> base² + perpendicular ² = hypontenuse ²
=> 12² + x² = (x+4)²
=> 144 + x² = x² + 16 + 8x
=> 8x = 144-16
=> 8x = 128
=> x = 128/8
=> x = 16 cm .
Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.
= 1/2 * 16 cm * 24cm .
= 192 cm²
<h3>
<u>★</u><u> </u><u>Hence</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the </u><u>tria</u><u>ngle</u><u> is</u><u> </u><u>1</u><u>9</u><u>2</u><u> </u><u>cm²</u><u> </u><u>.</u></h3>
Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
Answer:
Step-by-step explanation:
the perimeter of a square that has a side of (4x-3) is ; 4(4x-3) = 16x-12
Answer:
The option which is used to inscribe a square in a circle is option B
B. Construct a perpendicular bisector of the diameter of the circle
Step-by-step explanation:
The steps required to inscribe a square in a circle are;
1) Draw the circle using a compass
2) Draw the diameter of the circle, that passes through the center of the circle with a straight edge label the endpoint of the diameter X and Y
3) Construct the line perpendicular to the diameter of the circle and label the endpoints as A and B
The figure formed by joining the endpoints X, Y, A, and B is the inscribed square of the circle
Therefore, the correct option is to construct a perpendicular bisector of the diameter of the circle.