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neonofarm [45]
3 years ago
5

Solve for n. n+ 1 = 4(n-8) n = 1 n = 8 n = 11 C n = 16 Help? ;-;

Mathematics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

MMMMMMMMMMMMMMMM NO :)

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The perimeter of the figure to the right, made up of identical squares, is equal to 56 cm. What is the area of the figure?
Mamont248 [21]

The area of the square will be 196cm².

<h3>How to calculate the area?</h3>

It should be noted that the perimeter of a square is the addition of all its sides. Therefore, the length of the side will be:

= 56/4

= 14

Therefore, the area of the figure will be:

= 14²

= 14 × 14

= 196cm²

Learn more about area on:

brainly.com/question/25292087

#SPJ1

4 0
2 years ago
1
fredd [130]
Hi there I know the answer but it was confusing so it has to be D or B
6 0
3 years ago
Factorise (2t-7)²-(5t-4)² <br>with working pls​
sertanlavr [38]

Answer:

33+12t−21t^2

Step-by-step explanation:

(2t-7)²-(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².

4t^2−28t+49−(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².

4t^2−28t+49−(25t^2−40t+16)

To find the opposite of 25t^2

−40t+16, find the opposite of each term.

4t^2−28t+49−25t^2−40t+16

Combine 4t^2  and −25t^2  to get −21t^2.

−21t^2−28t+49+40t−16

Combine −28t and 40t to get 12t.

−21t^2+12t+49−16

Subtract 16 from 49 to get 33.

−21t^2+12t+33

Swap terms to the left side.

33+12t−21t^2

I hope this helped!

5 0
3 years ago
Which of these is the standard form of the following function?<br> f(n) = 7(7 - 1)2 + 3
mina [271]
F
(
n
)
=
87 That’s Standard form
6 0
3 years ago
-2(bx-5)=16 what is the value of x in terms of b and what is the value of x when b is 3?
Savatey [412]
Answer= -54



-2(bx-5)=16

If b is 3, then it changes to -2(3x-5)=16

We want to find x, right? Then we must do -2•3x and -2(-5). The result would be -6x and 10.

Then again, the equation would change -6x+10=16
Which would be -6x=6
Is x=6/6

And then x would be 1


Please tell me what I did wrong and if it is wrong, comment on this and I’ll fix my mistake!^^

7 0
3 years ago
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