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neonofarm [45]
2 years ago
5

Solve for n. n+ 1 = 4(n-8) n = 1 n = 8 n = 11 C n = 16 Help? ;-;

Mathematics
1 answer:
kari74 [83]2 years ago
8 0

Answer:

MMMMMMMMMMMMMMMM NO :)

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Anettt [7]

Answer:

The two polynomial CAN be 5x^4+5x^3+8x^2+x+6 and 5x^4+5x^3+8x^2+2x+13.

Step-by-step explanation:

Step 1: <u>Simplify the expression:</u>

2*2 + x + 3

4+x+3

x+7

Step 2: <u>Think of a random polynomial:</u>

5x^4+5x^3+8x^2+x+6

Step 3: <u>Either add your "random polynomial" by </u>x+7<u> or subtract it.</u>

<u>I want to add it so...</u>

5x^4+5x^3+8x^2+x+6+x+7

= 5x^4+5x^3+8x^2+2x+13

 Check by subtracting  5x^4+5x^3+8x^2+x+6 and 5x^4+5x^3+8x^2+2x+13.

         5x^4+5x^3+8x^2+2x+13

   -      5x^4+5x^3+8x^2+x+6

        _____________________

         0x^4 - 0x^3 -0x^2 +x +7 <em><u>or  </u></em>x+7<em><u /></em>

         

5 0
3 years ago
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