Iam sorry i cant see the qusetion
Because it directly passes through the x and y axis
Answer:
The probability of NOT hitting a boundary is (4/5).
Step-by-step explanation:
Let E: Be the event of hitting a boundary
now, Probability of any event E = 
Here, number of favorable outcomes = 6
So, P(E) = 
⇒Probability of hitting a six is 1/5
Now, P(E) + P(not E) = 1
So, P(not hitting a boundary ) = 1 - P(hitting a boundary)
= 1 - (1/5) = 4/5
Hence, the probability of NOT hitting a boundary is (4/5).
To find the expected value of the distribution, we multiply each outcome by it's probability. Doing this, we get that the expected value of defects on a skateboard is of
.
Outcomes and probabilities:
0 defects, 9/10 probability
1 defect, 1/20 probability
2 defects, 1/25 probability
3 defects, 1/100 probability.
Expected value:

Dividing both numerator and denominator by 4:

Thus, the expected value of defects on a skateboard is of
.
A similar problem is given at: brainly.com/question/23156292.
1x68
2x34
4x17
Hope that helps