Question: Find the value for x
201 = 11
40523 = 13
24680975012 = 432
101804102 = x
Answer:
After quite some time, I think there is too little to go on.
So based on these numbers alone, one single reliable answer can not be given.
Step-by-step explanation:
We need to find x.
Clearly some form of exponential growth is happening, because the numbers can not get that big by just adding or multiplying.
To find the exponent, you need to use the root function on your calculator. The standard root is based on ground number 2, so you need another ground number to be able to find the propper exponent.
IN GENERAL:
IN GENERAL:root( x, y ) = z
IN GENERAL:root( x, y ) = zz^x = y
root(11, 201) =1.61950189218624
so 1.61950189218624^11= 201
<em>Try</em> to predict the next number by a "formula". (There is no telling if this "formula" holds up in any other cases, but it seems to be working here at least):
y^2 + x^2 + 1 = next number (for xnew = xold +2)
201^2 + 11^2 + 1 =40523
xnew = xold +2 and xold was 11, so xnew = 11 + 2 = 13
root(13,40523) = 2.26171867395748
2.26171867395748^13 = 40523
<em>Trying to predict the next number by the formula does not work:</em>
<em>Trying to predict the next number by the formula does not work:40523^2 + 13^2 + 1 = 1642113699</em>
<em>Trying to predict the next number by the formula does not work:40523^2 + 13^2 + 1 = 1642113699Since 1642113699^2 is way too big for any following number, the conclusion must be: this seems to be a dead end.</em>
root(x,101804102) = z
z^x = 101804102
Try to predict the next number by applying <em>what we </em><em>do</em><em> know</em> in our "formula" (which is unreliable to begin with...).
y^2 + x^2 + 1 = next number (for xnew = xold +2)
101804102^2 + (x+2)^2 + 1 = 24680975012
101804102^2 + (x+2)^2 + 1 = 24680975012
root(432,24680975012) = 1.0569547485616
1.0569547485616^432 = 24680975012
After quite some time, I think there is too little to go on.
So based on these numbers alone, one single reliable answer can not be given.
