Answer:
x - 8 = 0
Step-by-step explanation:
Since, the cube root of a number is 2.
Let the number be x.
Therefore,
![\sqrt[3]{x} = 2 \\ cubing \: both \: sides \\ {( \sqrt[3]{x})}^{3} = {(2)}^{3} \\ x = 8 \\ x - 8 = 0](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%7D%20%20%3D%202%20%5C%5C%20%20cubing%20%5C%3A%20both%20%5C%3A%20sides%20%5C%5C%20%20%7B%28%20%5Csqrt%5B3%5D%7Bx%7D%29%7D%5E%7B3%7D%20%20%3D%20%20%7B%282%29%7D%5E%7B3%7D%20%20%5C%5C%20%20%20x%20%3D%208%20%5C%5C%20%20x%20-%208%20%3D%200)
Answer: x = -1/8
Step-by-step explanation:
Given the equation 9^x+1 - 13(3^x)+4=0
First, open the bracket, multiply 13 by 3
9^x+1 - 39^x+4=0
Combine like terms
9^x - 39^x +4 +1=0
40^x+5=0
Make x the subject
40^x=0 -5
40^x= -5
Divide both sides by 40
40^x/40=-5/40
x = -1/8
I hope this is clear, please mark as brainliest answer.