Answer : The moles of given compound is, 0.064 mole
Explanation : Given,
Mass of given compound = 40 g
Atomic mass of X = 50 amu
Atomic mass of Y = 45 amu
Atomic mass of Z = 10 amu
First we have to calculate the molar mass of given compound.
The given compound formula is, 
Molar mass of = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)
Molar mass of = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol
Now we have to calculate the moles of given compound.
Thus, the moles of given compound is, 0.064 mole
Answer:
What is the oxidation half reaction for iron?
The two elements involved, iron and chlorine, each change oxidation state; iron from +2 to +3, chlorine from 0 to -1. There are then effectively two half-reactions occurring. These changes can be represented in formulas by inserting appropriate electrons into each half-reaction: Fe2+ → Fe3+ + e.
Hope this helps..
Answer:
The overview of the subject is outlined underneath in the summary tab.
Explanation:
- The molar ratio seems to be essentially a balanced chemical equilibrium coefficient that implies or serves as a conversion factor for the product-related reactants.
- This ratio just says the reactant proportion which reacts, but not the exact quantity of the reacting product. Consequently, the molar ratio should only be used to provide theoretical instead of just a definite mass ratio.
Answer:
4.3 × 10⁻⁵ M s⁻¹
Explanation:
Step 1: Given data
- Rate constant (k): 2.20 × 10⁷ M⁻¹s⁻¹
- Concentration of NO ([NO]): 3.3 × 10⁻⁶ M
- Concentration of O₃ ([O₃]): 5.9 × 10⁻⁷ M
- First order with respect to both NO and O₃
Step 2: Write the balanced reaction
NO + O₃ ⇒ NO₂ + O₂
Step 3: Calculate the reaction rate
The rate law is:
rate = k × [NO] × [O₃]
rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M
rate = 4.3 × 10⁻⁵ M s⁻¹
