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Rzqust [24]
3 years ago
13

When comparing anions from the same group, larger size of A in the H-A bond increases / decreases (circle the correct answer) ac

id strength.
Chemistry
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

increases

Explanation:

The acid strength of any species depends on the stability of its conjugate base ,

The conjugate base is formed via the removal of the hydrogen ion .

Hence , more stable the conjugate base , more acidic would be the compound .

The conjugate base have a negative charge ,

Hence , larger the anion or the conjugate base , more stable it would be , because the negative charge will get dispersed on the larger species , hence will become stabilized .

Therefore ,

Larger the size of anion or the conjugate base , more stable would be the anion and more acidic would be the compound .

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2 years ago
1. A gas expands and does p-v work on the surroundings equal to
azamat

The change in energy of the system : -63 J

<h3>Further explanation</h3>

Given

279 J work

216 J heat

Required

The change in energy

Solution

Laws of thermodynamics 1

ΔU=Q+W

Rules :

  • receives heat, Q +  
  • releases heat, Q -  
  • work is done by a system, W -  
  • work is done on a system, W +  

a gas work on the surrounding : W =-279 J

a gas absorb heat from surrounding : Q = +216 J

Internal energy :

= -279+216

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3 0
2 years ago
How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?
maks197457 [2]

Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  46.07 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.229 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

8 0
3 years ago
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