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shutvik [7]
3 years ago
5

Which two integers is √93 between?​

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

between 9 and 10

Step-by-step explanation:

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Is the function even or odd?
sweet [91]

Answer:

f(\theta)=\cos(\theta) is an even function.

Step-by-step explanation:

Recall when it means when a function is even or odd. An even function has the following property:

f(-x)=f(x)

And an odd function has the following property:

f(-x)=-f(x)

So, let's test some values for cos(x).

Let's use π/3:

f(\pi/3)=\cos(\pi/3)

From the unit circle, was can see that this is 1/2 (refer to the x-coordinate).

Now, let's find -π/3. This is the same as 5π/3. Thus:

f(-\pi/3)=\cos(-\pi/3)

And again from the unit circle, we can see that this is 1/2.

Therefore, despite the negative, the function outputs the same value.

Cosine is an even function.

Notes:

Cosine is an even function and sine is an odd function. It's helpful to remember these as they can help you solve some trig problems!

6 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!
charle [14.2K]

Answer:

I think it is C.2920

3 0
2 years ago
Read 2 more answers
This is for algebra 2 and I got stuck on this anyone know this?
AnnZ [28]
You just simplify the fraction (so, 8/6 which is 4/3)

So your comes 4(square root of 35)/ 3 (square root of 15)
5 0
3 years ago
Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a
Mashutka [201]

Answer:

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

Step-by-step explanation:

Given

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Required

Make the denominator equal

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Factorize the denominator

\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}

\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}

\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}

\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}

<em>The expression now have the same denominator</em>

7 0
3 years ago
X^4-3x+1+4x^2-2x+8+x^3-9
Mariulka [41]

Answer:

??confusion I'm so confused

8 0
3 years ago
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