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3 years ago

5

Find the midpoint of the line segment with the given endpoints (-4,4),(-2,2)

1 answer:

Bingel [31]3 years ago

3 0

Answer:

(-3,3)

Step-by-step explanation:

use the midpoint formula

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Given g(x) = -x – 4, find g(-5).

riadik2000 [5.3K]

The value of g(-5) from the given. function; g(x) = -x – 4 is; g(-5) = 1

<h3>Evaluation of functions</h3>

The given function is;

g(x) = -x – 4

Hence, the value of g(-5) can be obtained by substituting -5 for x in the function as follows;

g(-5) = -(-5) -4

g(-5) = 5 -4

g(-5) = 1.

Read more on functions;

brainly.com/question/10439235

6 0

3 years ago

Read 2 more answers

The transformation of 'f' is represented by 'g'. Write a rule for g. f(x)=\root(3)(x). Then show your check steps.

podryga [215]

Answer:

$g(x)=-2\sqrt[3]x$

or

$g(x) = -2f(x)$

Step-by-step explanation:

Given

$f(x) = \sqrt[3]x$

Required

Write a rule for g(x)

See attachment for grid

From the attachment, we have:

$(x_1,y_1) = (-1,2)$

$(x_2,y_2) = (1,-2)$

We can represent g(x) as:

$g(x) = n * f(x)$

So, we have:

$g(x) = n * \sqrt[3]x$

For:

$(x_1,y_1) = (-1,2)$

$2 = n * \sqrt[3]{-1}$

This gives:

$2 = n * -1$

Solve for n

$n = \frac{2}{-1}$

$n = -2$

To confirm this value of n, we make use of:

$(x_2,y_2) = (1,-2)$

So, we have:

$-2 = n * \sqrt[3]1$

This gives:

$-2 = n * 1$

Solve for n

$n = \frac{-2}{1}$

$n = -2$

Hence:

$g(x) = n * \sqrt[3]x$

$g(x)=-2\sqrt[3]x$

or:

$g(x) = -2f(x)$

4 0

3 years ago

Solve for a.<br>g= 1+2a<br> -------<br> a

vladimir2022 [97]

Subtract g add 1 divide by 2a

8 0

3 years ago

Agent groot uses his secret spy camera to photograph some of his enemies that are plotting to take over the world. He takes 48 o

ehidna [41]

Answer:

40% of the photos are victor

Step-by-step explanation:

48/(48+32+40)

6 0

3 years ago

Write the equation of the conic section with the given properties:

timurjin [86]

Answer:

$\frac{x^2}{64} + \frac{y^2}{25} =1$

Step-by-step explanation:

An ellipse with vertices (-8, 0) and (8, 0)

Distance between two vertices = 2a

Distance between (-8,0) and (8,0) = 16

2a= 16

so a= 8

Vertex is (h+a,k)

we know a=8, so vertex is (h+8,k)

Now compare (h+8,k) with vertex (8,0) and find out h and k

h+8 =8, h=0

k =0

a minor axis of length 10.

Length of minor axis = 2b

2b = 10

so b = 5

General formula for the equation of horizontal ellipse is

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b} =1$

a= 8 , b=5 , h=0,k=0. equation becomes

$\frac{(x-0)^2}{8^2} + \frac{(y-0)^2}{5} =1$

$\frac{x^2}{64} + \frac{y^2}{25} =1$

5 0

3 years ago