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MrRa [10]
3 years ago
7

A rectangle has a perimeter of 26 cm, and one of its sides has a length of 5 cm. Sketch the rectangle and label all of its side

lengths.
Mathematics
1 answer:
jenyasd209 [6]3 years ago
7 0
The two shorter sides of the rectangle are 5cm each and the two longer ones are 8cm each. we know this because if one of the sides of the rectangle is 5cm that means the other side is also 5cm. if you add these two sides you get 10cm. if the total perimeter of the rectangle is 26cm and you know that two sides add up to 10cm then you subtract 10cm from 26cm. this will give you a remainder of 16cm for the remaining sides in question. if the total of the two remaining sides is 16cm that means that each of the remaining sides is 8cm long because 16/2 = 8
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What is the answer to this question? If x=y, then 6x=6y
Sliva [168]

Answer:

This is a true statement. I think that's what you're asking.

Step-by-step explanation:

It is true because if x=y, than 6x=6y because both sides have a 6 and x=y

8 0
3 years ago
The school's production of Romeo and Juliet began at 7:45 P.M. The first act lasted 1 hour and 35 minutes. The act was followed
Anika [276]
It should be 9:30 P.M.

7:45+ 15= 8
1 hour 35 minutes - 15= 1 hour 20

8+ 1 hour 20 minutes= 9:20
9:20+ 10= 9:30 P.M.
 
3 0
3 years ago
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Find all points on the curve y = cos x, 0 ≤ x ≤ 2π, where the tangent line is parallel to the line y = -x.
andre [41]

Answer:

90⁰

Step-by-step explanation:

y=cosx

y'= -sinx

eqñ of tangent is y=-x

slope of tangent =-1

we know...

slope of tangent = y' or derivative of y

-sin x = -1

sin x= 1

x = 90⁰

7 0
2 years ago
This is part of a bus timetable between Birmingham and Coventry (see attached image )
leva [86]

Answer:

a. 1 hour and 32 minutes b. 8:07

Step-by-step explanation:

a.8:34-7:02

b. 9 minutes +1 hour and 32 minutes+12 minutes=1.53 hours before 10=8:07

5 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
3 years ago
Read 2 more answers
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