Answer:
The correct answer is option d.
Explanation:
The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.
In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.
The correct answer is C, i.e., Passeur domesticus. According to binomial nomenclature, the name of the genus is started with a capital alphabet and name of the species is started with the lower alphabet. Further, it should also be in italics or alternatively may be underlined
Cell reproduction is MOST applicable to growing and developing in organisms. Hope this helps!
Answer: GROW and DEVELOP
I think it's when glycogen turns glycogen into glucose and vice versa. Not too sure though.
