Answer:
The answer to this question can be described as follows:
Step-by-step explanation:
- In Additional A and B implies, that ABCD is a parallelogram. So, there diagonals AC and BD were intersecting.
- AKO and CMO are similar to BC, for they are congruent. There are, therefore, congruent of MCO and KAO.
- The AOK and COM triangles are at least identical, so these triangles are congruent because the bisects AC are of BD .
- Then KO and MO are congruent since they are matching congrue sides, that's why MO≅KO is its points.
Answer:
k² + 10k + 24
Step-by-step explanation:
First, the square has side length k. Now in rectangle,
l= k+6
b= k+4
Ar. of rectangle= l×b
Eq.
(k+6)(k+4)
opening bracket,
k² + 6k + 4k + 24
k² + 10k +24
Answer:
30mm
Step-by-step explanation:
Small Parallelogram= 5×10
Big Parallelogram= 15×?
15÷5=3
?÷10=3
?=30
30÷10=3
Answer:
26
Step-by-step explanation:
Remember that when the exponents look like this (5^2)^-3, you multiply the exponents together
when it looks like this:
5^3 x 5^2 you add the exponents
so my example would equal 5^5
also remember that you can’t have negative exponents
To solve your problem:
1. multiply the exponents here: (5^2)^-3
2. add the exponents in the next step when you multiply by the 5^4
3. now, you should get a negative exponent on the top, and you already have one on the bottom. to get rid of these negative exponents, move the one in the denominator to the numerator and vice versa
so when you move the 5^-4 in the denominator to the numerator, it becomes 5^4
4. now, you simplify. you can either subtract the exponents and do it that way, or you can solve the exponents and then divide. either way will work, although the first is easier