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kkurt [141]
3 years ago
6

What is the name of the variable that changes by itself in an experiment?

Chemistry
1 answer:
3241004551 [841]3 years ago
3 0

Answer:

the independent variable (sometimes known as the manipulated variable )

Explanation:

is the variable whose change isn't affected by any other variable in the experiment

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(4.5 x 10^24 molecules) x (60.013 g / 6.022 x 10^23) = 448 grams or 4.484 x 10^2 grams = Answer
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What causes the electrons to move and form static electricity?
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A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s
Talja [164]

<u>Answer:</u> The enthalpy of the reaction is -4134.3 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of calorimeter = 1.900 kg = 1900 g  (Conversion factor:  1 kg = 1000 g)

c = heat capacity of calorimeter = 3.21 J/g.K

\Delta T = change in temperature = 4.542 K

Putting values in above equation, we get:

q=1900g\times 3.21J/g.K\times 4.542K=27701.66J=27.7kJ

Heat released by the calorimeter will be equal to the heat absorbed by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hexane = 0.580 g

Molar mass of hexane = 86.18 g/mol

Putting values in above equation, we get:

\text{Moles of hexane}=\frac{0.580g}{86.18g/mol}=0.0067mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -27.7 kJ

n = number of moles of hexane= 0.0067 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-27.7kJ}{0.0067mol}=-4134.3kJ/mol

Hence, the enthalpy of the reaction is -4134.3 kJ/mol

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Both lowercase letters have to be present for the recessive trait to show.<br> A. True<br> B. False
BabaBlast [244]
True if you had an uppercase and a lowercase it would show the dominant trait
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