Concept:
When an atom has incomplete number of electron in its outermost orbit then it has great tendency to react with another atom which satisfies their octate either by sharing or by transferring their electrons. The involved electrons are called valence electrons.
In case of electrovalent compound, the valance electron complete their octate by transferring their valence electrons while in the covalent compound, they complete their octate by the sharing of their valence electrons.
Hence, the valence electron of the atom is involved in chemical bonding with other atoms.
1 mole of any substance has Avagadro number of molecules and it's weight is equal to its molecular weight.
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Answer 1:
Molecular weight of HNO3 = 63.01 g/mol
Therefore, 1mole of HNO3 = 63.03 g
Hence, 15.7 mole of HNO3 = 63.03 X 15.7
= 989.57 g
Thus, mass of 15.7 mole of HNO3 = 989.57 g
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Answer 2:
Molecular weight of H2O2 = 34.01 g/mol
Therefore, 1mole of H2O2 = 34.01g
Hence, 0.00104 mole of H2O2 = 34.01 X 0.00104
= 0.03537 g
Thus, mass of 0.00104 mole of H2O2 is 0.03537 g
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Answer 3:
Molecular weight of SO2 = 64.07 g/mol
Therefore, 1mole of SO2 = 64.07 g
Hence, 72.1 mmole of SO2 = 64.07 X 0.0721
= 4.619 g
Thus, mass of 72.1 mm of SO2 is 4.619 g
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Answer 4:
Molecular weight of XeF2 = 169.29 g/mol
Therefore, 1mole of XeF2 = 169.29 g
Hence, 1.23 mole of XeF2 = 169.29 X 1.23
= 208.23 g
Thus, mass of 1.23 mole of XeF2 is 208.23 g
Answer:
Problem, Variables, Hypothesis, Research, Procedure, Data, Conclusion.
Explanation:
First, you have to know what the problem that you're talking about is. Then, you have to know the independent, dependent, and controlled variables are in order to make a hypothesis. Then do research about the topic. After that, you make the procedure your experiment, if that's what your doing. Then after the experiment, you find the data. Using that data, you make a conclusion.
I got 9.25527 for the pKa
<span>then for the Henderson-Hasselbalch equation: </span>
<span>9.00=9.25527+log(.600/acid) </span>
10^(-.25527)=(.600/acid)correct to this line. Then
0.5556 = 0.6/acid and
acid = 0.6/0.5556 = 1.08 which is the reciprocal of your number)
<span>.5556/.600M=acid </span>
<span>acid=.925925...M </span>
<span>(.925925)*2.10L= Molarity</span>
Answer:
196 gdm-3
Explanation:
There are two major units of concentration, moldm-3 and gdm-3. The first unit refers to molar concentration while the second unit refers to mass concentration. Both units are useful in chemistry when describing the concentration of solutions as deemed expedient in each particular case.
Here we are required to compute the mass concentration from the molar concentration. We must recall that; mass concentration= molar concentration × molar mass
Let us first obtain the molar mass of H2SO4 from the relative atomic masses given=
2(1) + 32 + 4(16) = 98 gmol-1
Molar concentration of H2SO4 = 2 moldm-3
Mass concentration= 2 moldm-3 × 98 gmol-1
Mass concentration = 196 gdm-3
