How to solve trapezoid property

Mathematics

1 answer:

masha68 [24]2 years ago

8 0

<h2>★<u>Answer</u></h2>

The properties of trapezoid apply by definition (parallel bases).
The legs are congruent by definition.
The lower base angles are congruent.
The upper base angles are congruent.
Any lower base angle is supplementary to any upper base angle.

<h3> $\: Hope \: it \: Helps!$ </h3>

You might be interested in

Draw a model to represent the product of 41x 16

Vladimir79 [104]

First you have to multiply 6*1=6 and 6*4=24 that would equal 246
next, you have to add a zero and multiply 1*1=1 and 1*4=4 that would come out to 410.
then you add 246+410. the answer to this equation would be the answer to the whole problem.

4 0

2 years ago

Read 2 more answers

In the equation y= -2x what are the possible values of y?

cestrela7 [59]

Y depends on x. And x are the real numbers.

Hope this helps!

8 0

2 years ago

Which term is correct when simplifying √128?<br><br> A.) 16<br> B.) 12<br> C.) 10<br> D.) 8√2

alina1380 [7]

When dealing with roots, we want to factor to see if it's possible

$128 = 2 \times 64$
$= 2 \times 2 \times 32$
$= 2 \times 2 \times 2 \times 16$
$= 2 \times 2 \times 2 \times 2 \times 8$
$= 2 \times 2 \times 2 \times 2 \times 2 \times 4$
$= 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$

now since we're dealing with square roots, we circle every pair of numbers we see in the final factoring
so..
$= (2 \times 2) \times (2 \times 2) \times (2 \times 2) \times 2$

now for every circled pair, we take only 1 of the 2 circled and bring it outside
anything left uncircled stays inside the root
so..
$= 2 \times 2 \times 2 \times \sqrt{2}$

now simply multiply
$8 \sqrt{2}$