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lara31 [8.8K]
3 years ago
9

How to solve trapezoid property​

Mathematics
1 answer:
masha68 [24]3 years ago
8 0
<h2>★<u>Answer</u></h2>
  • The properties of trapezoid apply by definition (parallel bases).
  • The legs are congruent by definition.
  • The lower base angles are congruent.
  • The upper base angles are congruent.
  • Any lower base angle is supplementary to any upper base angle.
<h3>\: Hope \: it \: Helps!</h3>
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A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must inv
Pani-rosa [81]

Hello again!

when he invested $4000 at 5% he increased his income from 0 to 200

adding 4% of 3500 increased it by 140

totaling to $340

he has $2500 left. and he needs $160 more income

160 is 6.4% of 2500

so he needs to invest the remaining $2500 at 6.4% to get the last $160

of his income

I hope this helps, and have a nice day!

3 0
4 years ago
Please help I will give brainliest! I just need 22 and 23 please! Thank you! (And it’s related to ordered pairs by the way!)
cluponka [151]

Answer:

22. B1, G1 (from left to right)

23. E5

Step-by-step explanation:

7 0
3 years ago
Jackie buys 51 kilograms of rice for the school cafeteria. How many grams of rice did Jackie buy?​
tresset_1 [31]
Jackie bought 51000 grams of rice. Because there are 1000 grams in a kilogram so, 51 x 1000 is 51000.
3 0
3 years ago
The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%
vagabundo [1.1K]

Answer:

1) \chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

2) p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}

Where O rpresent the observed values and E the expected values.  

State the null and alternative hypothesis

Null hypothesis: The distribution  is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution  is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

E = \% Grand total

E_{Catfish}=500*0.3=150

E_{Bass}=500*0.15=75

E_{Bluegill}=500*0.4=200

E_{Pike}=500*0.15=75

Part 1: Calculate the statistic

\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

\chi^2 =16.313

Calculate the critical value

First we need to calculate the degrees of freedom given by:

df= (categories-1)=(4-1)= 3

Since the confidence provided is 95% the significance would be \alpha=1-0.95=0.05 and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be \chi^2_{crit}=7.815

We can calculate also the p value:

p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

5 0
3 years ago
The sum of two consecutive odd integers is 80? What is the smaller number?​
Zielflug [23.3K]

Answer:

39 , 41

Step-by-step explanation:

Let the two consecutive odd numbers be (2x - 3) and (2x- 1)

2x - 1 + 2x -3 = 80

4x - 4 = 80

4x = 80 + 4

4x = 84

x = 84/4

x = 21

2x - 3 = 2*21 - 3 = 42-3 = 39

2x-1 = 2*21 - 1 = 42-1 = 41

4 0
4 years ago
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