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3 years ago

How to solve trapezoid property

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

<h2>★<u>Answer</u></h2>

The properties of trapezoid apply by definition (parallel bases).
The legs are congruent by definition.
The lower base angles are congruent.
The upper base angles are congruent.
Any lower base angle is supplementary to any upper base angle.

<h3> $\: Hope \: it \: Helps!$ </h3>

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Can somebody please help me??:(

arlik [135]

Answer:

its B

Step-by-step explanation:

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3 years ago

Solve the system by elimination

Alja [10]

First of all we will eliminate x from our equations. In order to do that we will use our first and second equation and then we will use second and third equation.

$-2x+2y+3z=0...(1)\\-2x-y+z=-3....(2)$

Upon subtracting 2 equation from 1 we will get,

$3y+2z=3....(4)$

Now we will use second and third equation to eliminate x.

$-2x-y+z=-3....(2)\\2x+3y+3z=5....(3)$

Adding 2nd and 3rd equation we will get,

$2y+4z=2....(5)$

Now we will find out y from our 4th and 5th equation.

$2*(3y+2z)=2*3....(4)\\2y+4z=2....(5)$

Upon subtracting 5th equation from 4th equation we will get,

$4y=4\\y=1$

Now let us find out z by substituting y's value in 5th equation.

$2*1+4z=2\\4z=2-2\\z=0$

Now we will find x from by substituting y and z's value in equation 1.

$-2x+2*1+3*0=0\\-2x+2=0\\2=2x\\x=1$

Therefore, x=1, y=1 and z=0 is the solution of the given system.

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4 years ago

What's the slope of the line passing through the points (-4, 7) and (2, -8)?

Alja [10]

Y1-y2/x1-x2

7+8/-4-2
15/-6
answer: -5/2

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3 years ago

Explain how to divide an amount by 2. Use the terms dividend, divisor and quotient

Sergio039 [100]

Try first and see what u get don't always give up try your best and do your best

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3 years ago

URGENT! WILL GIVE BRAINLIEST!!

IgorC [24]

Answer:

Option C) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Step-by-step explanation:

Given infinite sequence is ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Option B) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Now verify $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

$a_{n}=m-b+m(n-1)$

When n=1, $a_{1}=m-b+m(1-1)$

$=m-b+0$

$a_{1}=m-b\neq m+b$

When n=2, $a_{2}=m-b+m(2-1)$

$=m-b+m$

$a_{2}=2m-b\neq 2m+b$

When n=3, $a_{3}=m-b+m(3-1)$

$=m-b+2m$

$a_{3}=3m-b\neq 3m+b$

and so on.

Therfore $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Therefore option C) is correct

5 0

4 years ago

How to solve trapezoid property​

How to solve trapezoid property