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kiruha [24]
3 years ago
13

Why is the door handle

Physics
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer:

The further the distance from the pivot the greater the force

Explanation:

Practical example below

Distance of door handle is 5m. Force is 5N

Moment = Force × distance

=5×5

=25Nm

Distance of door handle is 7m. Force is 5N

= 7×5

=35Nm

Therefore proven correct

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1. A 1 kg cart moving with a speed of 3 m/s collides with a 2 kg cart at rest. If the carts stick together after the collision,
erica [24]

Answer:

The final speed of the two carts stuck together after the collision is 1 m/s

Explanation:

This is an example of an inelastic collision where two separate carts each with different momentum collide and become a single object.

The conservation of momentum (p) equation is: p_{1i}+p_{2i}=p_f where p_{1i} is the initial momentum of cart 1: p_{1i}=m_1\,*\,v_{1i}=1\,kg\,*\,3\,\frac{m}{s} = 3 \frac{kg*m}{s}

Notice that cart 2 is at rest, therefore its velocity is zero, which makes its initial momentum zero: p_{2i}=m_2\,*\,v_{2i}= 2\,kg \,*0\,\frac{m}{s} =0

The final momentum (p_f) for which we don't know the velocity (v_f) is the product of the final mass (addition of the two masses) times the final velocity of this new object (two carts stuck together):

p_f=(m_1+m_2)* v_f = 3\,kg\,*\,v_f

Now we re-write the conservation of momentum equation to isolate and obtain the unknown final velocity:

p_{1i}+p_{2i}=p_f\\3\,\frac{m*kg}{s}+0=3\,kg\,*\,v_f\\3\,\frac{m*kg}{s}=3\,kg\,*\,v_f\\v_f=\frac{3}{3}\, \frac{m}{s} \\v_f=1\,\frac{m}{s}

7 0
3 years ago
An electron moves along the z-axis with vz=4.1Ã107m/s. As it passes the origin, what are the strength and direction of the magne
Artist 52 [7]

Answer:

a

The value of magnetic field is B_a=6.56*10^{-19} T

In the direction of the positive x - axis

b

The value of magnetic field is B_a=6.56*10^{-19} T

In the direction of the positive z - axis

Explanation:

From the question we are told that

         The velocity of the electron is v_z = 4.1*10^{7}m/s

Considering the first position

    The equation for the magnetic field is

                    \= B = \frac{\mu_0}{ 4 \pi} \frac{q \=v * \= r}{r^2}

 Now r = \sqrt{i^2 + j^2 + k^2}

  substituting values

           r = \sqrt{1^2 +0^2 +0^2}

              = 1

          \= r = \frac{\r r}{r}

        \r r = 1 i + 0j + 0k

Therefore \= r = \frac{1i + 0j + 0k}{1}

                   = i

So   Substituting  4 \pi *10^ {-7} for \mu_o , 1.602 *10^{-19} for q

            \= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * i}{1^2}

                 \= B_a=6.56*10^{-19} T (i)

Considering the second  position

    Here

               r = \sqrt{0^2 + 0^2 + 2^2}

                  =2

              \= r = \frac{\r r}{r}

              \r r = 0 i + 0j + 2k

            \= r = \frac{0i + 0j + 2k}{2}

               = k

 So   Substituting  4 \pi *10^ {-7} for \mu_o , 1.602 *10^{-19} for q

            \= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * k}{1^2}

                 \= B_a=6.56*10^{-19} T (k)

6 0
4 years ago
Which are the following are pure substance?
Jobisdone [24]
A pure substance is chemically combined

Therefore a compound is a pure substance because it cant be broken down physically

All elements are pure substances, along with tin, diamond, and etc...
6 0
4 years ago
Read 2 more answers
A softball with a mass of 0.11 kg goes moves at a speed of 12 m/s, then the ball is hit by a bat and rebounds in the opposite di
dimulka [17.4K]
=1244 and that's from my math book
7 0
3 years ago
You are outdoors when you hear the constant chirp of a still cricket. You start walking toward the cricket and at some point you
givi [52]

Answer:

4) True, the distance was reduced by a de factor 2

Explanation:

To analyze the statements, let's first see how the sound is produced

The cricket makes the sound rubbed its legs, the energy needed to produce it is constant, after the sound is produced it expands in all directions and this wave is subject to the law of energy conservation.

By expanding in all directions we can assume that the energy for the time that is the power of the sound is distributed over a sphere with different radii each time. The perceived intensity is defined as the power per unit area

       I = P / A

Where P is the power, A are the areas and I are the intensities heard by the person

Let's clear the power and match, for two different radii (distances)    

      P = I₁ A₁ = I₂ A₂

The area of ​​a sphere is

     A = 4π R₂

     I₂ = I₁ A₁ / A₂

     I₂ = I₁ 4π R₁² / 4π R₂²

     I₂ = I₁ R₁² / R₂²

Let's analyze this last equation for the situation presented if the intensity increases 4 times, substitute

    I₂ = 4 I₁

    4 I₁ = I₁ R₁² / R₂²

   R₂ = R₁ / 2

We see that to increase the intensity 4 times the distance was reduced twice

Now we can analyze the expressions given

2) False, the power is constant, the cricket always does the same job

3) False, the speed of the wave is constant in the air

4) True, the distance was reduced by a de factor 2

3 0
3 years ago
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