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cricket20 [7]
3 years ago
15

Guy can someone help me with this

Physics
1 answer:
Mrac [35]3 years ago
3 0

I believe it should be B.

Here’s one desctiption:

When the balloon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall. Although the wall should normally have a neutral charge, the charges within it can rearrange so that a positively charged area attracts the negatively charged balloon

Hopefully it’s right!

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What are the effects of noise?​
slega [8]

Answer:

Noise making has led to loss on hearing.

Explanation:

Supposing you like engaging in parties because of the noise of the sound system it can cause loss on hearing if continued for long

6 0
4 years ago
a railroad tie weights 920 N and is 2.6 m long. How much force is required to: pick it up off the ground? lift one end and rotat
lukranit [14]

1) The minimum force needed is 920 N

2) The minimum force is 460 N

3) The minimum force is 598 N

Explanation:

1)

We can answer this part by simply looking at the forces involved. In fact, there are two forces acting on the railroad:

  • Its weight, W, acting downward
  • The force applied to lift it, F, upward

So the net force on the railroad is

\sum F = F - W

where

W = 920 N is the weight of the railroad

In order to lift the railroad, the net force must be upward, so

\sum F \geq 0

And therefore

F\geq W

which means that the minimum force needed is equal to the weight of the railroad, 920 N.

2)

In this case, we have to use the principle of equilibrium of moments.

In fact, when the railroad rotates uniformly (=constant angular speed) about its end, it means that the moment produced by the weight (acting in one direction) is equal to the moment produced by the force applied (acting in the other direction). Therefore, we can write:

W \frac{L}{2} = F L

where

W = 920 N is the weight

L = 2.6 m is the length of the railroad

F is the force applied

We wrote L/2 on the left of the equation because the weight acts at the center of mass of the railroad (located at the midpoint), while on the right it is L because the force F is applied at the end of the railroad.

Solving for F,

F=\frac{W}{2}=\frac{920}{2}=460 N

3)

This problem is similar to the previous part, however in this case, the force applied F is applied 0.6 m from the end, pivoting around the opposite end.

This means that the distance between the point of application of the force F and the pivot is

L' = L - 0.6

where

L = 2.6 m

Therefore the equation for the equilibrium of moments becomes

W\frac{L}{2}=F(L-0.6)

and substituting

W = 920 N

L = 2.6

We find the magnitude of F:

W\frac{2.6}{2}=F(2.6-0.6)\\1.3W = 2F\\F=\frac{1.3}{2}W=\frac{1.3}{2}(920)=598 N

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
3 years ago
A scientific theory is_____.
natta225 [31]

Answer:

B. A well-tested explanation for a widely accepted hypothesis

Explanation:

This is true about a scientific theory going by the fact of it being a well tested explanation. For example, in one of the Newtons law of motion which he stated to be<em> "To every action, there is equal and opposite reaction", </em><em>the hypothesis has been known till he was able to offer a well tested explanations with calculations showing that, it was actually true.</em>

6 0
3 years ago
Based electromagnetic spectrum? on its surface temperature of 6,000 K, most photons that leave the Sun's surface lie in which re
masha68 [24]

Answer:

option C

Explanation:

given,

Temperature of the surface = 6000 K

using formula to calculate \lambda_{max}

\lambda_{max} = \dfrac{0.0029\ K.m}{T}

\lambda_{max} is the maximum wavelength emission in meter.

T is the temperature in kelvin.

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = 4.8333 \times 10^{-7}

\lambda_{max} = 4833\ A^0

the wavelength is in Visible range

The Correct answer is option C

7 0
4 years ago
You push a 10N object 10 meters. How much work was done on the object.
Agata [3.3K]
Work = force times distance

10*10=100

100J of work done
6 0
3 years ago
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