Answer:
Yes, your answers are correct.
The volume of a cone is given by V = 1/3πr²h. Since the diameter of the first cone is 4, the radius is 2; therefore the volume is
V = 1/3π(2²)(8) = 32π/3
We divide the volume of the sink, 2000π/3, by the volume of the cone:
2000π/3 ÷ 32π/3 = 2000π/3 × 3/32π = 6000π/96π = 62.5 ≈ 63.
The diameter of the second conical cup is 8, so the radius is 4. The volume then is:
V = 1/3π(4²)(8) = 128π/3
Dividing the volume of the sink, 2000π/3, by 128π/3:
2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16
34/w = 40/100
40w = 340
340/40 =w
w= 8.5 or 85/ 10
Answer:
There are 0 solutions to this problem because it cannot be re-arranged logically enough to come to a new conclusion.
Answer:
(IQR) interquartile range = 5
Step-by-step explanation:
Lower quartile: 48
Upper quartile: 53
Median: 52
Lowest value: 46
Highest value: 55
(IQR) interquartile range: Upper quartile - Lower quartile = final answer
(IQR) interquartile range: 53 - 48 = 5
G equals 4, as side both sides by 2, then add three, and divide by four.
