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What equation describes conservation of charge?

Phantasy [73]

Answer:

The equation which describes conservation of charge is $Q_{initial} - Q_{final } = 0$

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = $Q_{initial}$

let the sum of the final charges = $Q_{final}$

$Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0$

Therefore, the equation which describes conservation of charge is $Q_{initial} - Q_{final } = 0$

6 0

3 years ago

If2.0J of work is done in raising a 180g apple how far is it lifted?

Alex

We know, W = F * s
W = mg * s

Here, w = 2 J
m = 180 g = 0.180 Kg
g = 9.8 m/s

Substitute their values into the expression:
2 = 0.180*9.8 * s
1.764s = 2
s = 2 / 1.764
s = 1.13 meter

In short, Your Final Answer is 1.13 m

Hope this helps!

7 0

3 years ago

To understand the photoelectric effect physiciests should view light as having what type of properties?

fenix001 [56]

Answer:

Particle

Explanation:

To understand photoelectric effect the physicists has to view light as a particle and not wave. The wave nature of the light could not explain the phenomenon of photoelectric effect.

Photoelectric effect is emission of electrons from a material when electromagnetic radiation(Light) is incident on it. These emitted electrons are called photoelectrons.

The explain this effect Einstein proposed that beam of light is can not be a wave propagating through space, but a swarm of discrete energy packets, called as photons.

5 0

3 years ago

A 60 [Hz] high-voltagepower line carries a current of 1000 [A]. The power line is at a height of 50 [m] above the earth. What is

omeli [17]

Answer:

The magnitude of the magneticfield B[T] at a point on the surface of the earth directly below the power line is B=1.496x10^(-6) T.

Explanation:

The distance from the wire to a point in the surface is the heigth of the wire.

The formula for the magnetic field on any point at distance R from a wire conducting alternating current is:

$B=\frac{\mu_0I}{2\pi R} =\frac{(4\pi\cdot 10^{-7}T\cdot m/A)(1000\,A)}{2\pi \cdot 50\,m} =1.496\cdot10^{-6}\,T$

4 0

3 years ago

Suppose a cheetah running at a velocity of 5 m/s east slows down. After 15 seconds, the cheetah has reached a velocity of 25 m/s

Darina [25.2K]

Answer:

1.33m/s²

Explanation:

Given parameters:

Initial velocity = 5m/s

Final velocity = 25m/s

Time taken = 15seconds

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time.

Acceleration = $\frac{v - u}{t}$

v is the final velocity

u is the initial velocity

t is the time taken

So;

Acceleration = $\frac{25 - 5}{15}$ = 1.33m/s²

5 0

3 years ago