Answer:
(a) 16.5528 V
(b) 827.64 W
Explanation:
(a)
The formula for maximum emf produced in a coil is given as
E₀ = BANω.................. Equation 1
Where E₀ = maximum emf produced in the coil, B = magnetic Field, A = Area of the rectangular coil, N = number of turns, ω = angular velocity.
Given: B = 1.9 T, N = 44 turns, ω = 110 rad/s, A = 2×9 = 18 cm² = 18/10000 = 0.0018 m²
Substitute into equation 1
E₀ = 1.9(44)(110)(0.0018)
E₀ = 16.5528 V
(b)
Maximum power
P₀ = E₀²/R...................... Equation 2
Where R = Resistance.
Given: R = 50 ohms, E₀ = 16.5528 V
Substitute into equation 2
P₀ = 50(16.5528)
P₀ = 827.64 W
<span>a. the chemical energy stored in living things i hope this helps you</span>
The final momentum of the system would be 6680 Kg m/s
<h3>What is momentum?</h3>
It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
Mathematically the formula of the momentum is
P = mv
Two cars are driving toward each other in a straight line. Car A is 1400 kg and driving at 11 m/s. Car B is 1090 kg and driving at 8 m/s. If the two cars collide inelastically, As we know that the momentum of a system is conserved during the collision
initial momentum = final momentum
the initial momentum of the system = 1400 ×11 + 1090×(-8)
= 6680 Kg m/s
The final momentum of the system = 6680 Kg m/s
Thus,The final momentum of the system would be 6680 Kg m/s
Learn more about momentum from here
brainly.com/question/17662202
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Troposphere. The troposphere is the lowest layer of our atmosphere.
Stratosphere. The infamous ozone layer is found within the stratosphere.
Mesosphere. Most meteors burn up in the mesosphere.
Thermosphere. Many satellites actually orbit Earth within the thermosphere
Exosphere. Considered to be the actual "final frontier"
Ionosphere. The electrically charged atoms and molecules that are formed in this way are called ions, giving the ionosphere its name
Answer:
1.19cm^3 of glycerine
Explanation:
Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:
Volume of spill glycerine = change in volume of glycerine - change in volume of aluminum
Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature
coefficient of volume expansion of aluminum = coefficient of linear expansion of aluminum*3 = 23*10^-6 * 3 = 0.69*10^-4 oC^-1
Change in temperature = 41-23 = 18oC
Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3
