Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.
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Answer: B
Incomplete question as we have not told which quantity to find.So the complete question is here
A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.Given this, how large a current does it carry?
Answer:
![I=2.021A](https://tex.z-dn.net/?f=I%3D2.021A)
Explanation:
Magnetic field B=1.5 T
Length L=2.2mm =0.0022m
Number of turns N=1300 turns
To find
Current I
Solution
From the magnetic at the center of loop we know that:
![B=uI\frac{N}{L}](https://tex.z-dn.net/?f=B%3DuI%5Cfrac%7BN%7D%7BL%7D)
Substitute the given values
![B=uI\frac{N}{L}\\ as\\u=4\pi *10^{-7} T.A/m\\So\\B=uI\frac{N}{L}\\I=\frac{LB}{Nu}\\ I=\frac{0.0022m(1.5T)}{(1300)(4\pi *10^{-7} T.A/m)}\\I=2.021A](https://tex.z-dn.net/?f=B%3DuI%5Cfrac%7BN%7D%7BL%7D%5C%5C%20as%5C%5Cu%3D4%5Cpi%20%2A10%5E%7B-7%7D%20%20T.A%2Fm%5C%5CSo%5C%5CB%3DuI%5Cfrac%7BN%7D%7BL%7D%5C%5CI%3D%5Cfrac%7BLB%7D%7BNu%7D%5C%5C%20I%3D%5Cfrac%7B0.0022m%281.5T%29%7D%7B%281300%29%284%5Cpi%20%2A10%5E%7B-7%7D%20%20T.A%2Fm%29%7D%5C%5CI%3D2.021A)
The answer for the problem is explained through this:
The following are the given:
F = 4.719 N, the applied force
a = 33 m/s², the acceleration
Let m = the mass.
By definition of the formula:
F = m*a
Therefore,
m = F/a
= (4.719 N)/(33 m/s²)
= 0.143 kg
Answer: 0.143 kg