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3 years ago

11

A glass rod is rubbed briefly with silk and the rod becomes able to attract and lift a number of small pieces of paper. If the r

od is rubbed with silk for a longer period of time, explain what will happen and why.
QUICKLY PLEASE!

2 answers:

ser-zykov [4K]3 years ago

8 0

Answer:

it will have a stronger attraction force

Explanation:

PIT_PIT [208]3 years ago

3 0

The person above is correct

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A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?

ludmilkaskok [199]

The answer is 24.84kJ.

We apply the expression for the work done by the heat engine is,

$W=E_{i n}-E_{o u t}$ . Putting all given values in the equation we get the final answer.

What is heat engine?

A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$ . The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$ .
The expression for the work done by the heat engine is, $W=E_{i n}-E_{o u t}$
Substituting the given values in the above expression, we will get $W =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}$ =24.84kJ.
Thus, the work done by the heat engine is 24.84kJ.

To learn more about heat engine visit: brainly.com/question/15735984

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2 years ago

Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the r

madam [21]

Answer: 0.3872m

Explanation:

q= 100nC --> 100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

$E= K\frac{q}{r^{2} }$ --> $r=\sqrt{\frac{kq}{E} }$ Despejas "r"

Resuelves

<h3> $r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9} C)}{6000N/C} }$ (la x es por, no es una variable)</h3><h3>r= 0.3872983346m</h3>

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3 years ago

Your neighbor Paul has rented a truck with a loading ramp. The ramp is tilted upward at 25°, and Paul is pulling a large crate u

Alisiya [41]

Explanation:

It is given that,

The ramp is tilted upwards at 25 degrees and Paul is pulling a large crate up the ramp with a rope that angles 10° above the ramp.

Total angle with respect to ramp is 35 degrees.

If Paul pulls with a force of 550 N.

The horizontal component of the force is given by :

$F_x=F\ cos\theta$

$F_x=550\ cos(35)$

$F_x=450.53\ N$

The vertical component of the force is given by :

$F_y=F\ sin\theta$

$F_y=550\ sin(35)$

$F_y=315.46\ N$

Hence, this is the required solution.

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3 years ago

A 49.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.584 and 0.399,

NISA [10]

Answer:

(a) Force must be grater than 283.87 N

(B) Force will be equal to 193.945 N

Explanation:

We have given mass of the crate m = 49.6 kg

Acceleration due to gravity $g=9.8m/sec^2$

Coefficient of static friction $\mu _s=0.584$

Coefficient of kinetic friction $\mu _k=0.399$

(a) Static friction force is given by $F_S=\mu _smg=0.584\times 49.6\times 9.8=283.8707N$

So to just start the crate moving we have to apply more force than 283.87 N

(B) This force will be equal to kinetic friction force

We know that kinetic friction force is given by $F_k=\mu _kmg=0.399\times 49.6\times 9.8=193.945N$

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3 years ago

What is the difference between cytology and histology

bulgar [2K]

Explanation:

what is the difference between cytology and histology

Histology involves the study of tissue and Cytology involves the study of cells, both of which are derived from various organs of the human body. The Histology laboratory is responsible for the preparation of tissue for diagnosis by Pathologists.

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