Answer:
(a): The bird speed after swallowing the insect is V= 4.83 m/s
(b): The impulse on the bird is I= 0.3 kg m/s
(c): The force between the bird and the insect is F= 20 N
Explanation:
ma= 0.3 kg
va= 6 m/s
mb= 0.01kg
vb= 30 m/s
(ma*va - mb*vb) / (ma+mb) = V
V= 4.83 m/s (a)
I= mb * vb
I= 0.3 kg m/s (b)
F*t= I
F= I/t
F= 20 N (c)
Answer: 1477.78 N
Explanation:
Let's assume that the cross sectional area of the smaller piston be A1
let's also assume the cross sectional area of the larger piston be A2
We assume the force applied to the smaller piston be F1
We also assume the force applied to the larger piston be F2
we then use the formula
F1/A1 = F2/A2
From our question,
The radius of the smaller piston is 5 cm = 0.05 m
The radius of the larger piston is 15 cm = 0.15 m
The force of the larger piston is 13300 N
The force of the smaller piston is unknown = F
A1 = πr² = 3.142 * 0.05² = 0.007855 m²
A2 = πr² = 3.142 * 0.15² = 0.070695 m²
F1/0.007855 = 13300/0.070695
F1 = (13300 * 0.007855) / 0.070695
F1 = 104.4715 / 0.070695
F1 = 1477.78 N
Thus, the force the compressed air must exert is 1477.78 N
Answer:
Gravitational potential energy stored is 9.8 J.
Given:
G = 9.8 
height = 0.5 m
mass = 2 kg
To find:
Gravitation Potential energy stored = ?
Formula used:
Potential energy = mGh
m = mass
G = acceleration due to gravity
h = height
Solution:
Potential energy of the object is given by,
Potential energy = mGh
m = mass
G = acceleration due to gravity
h = height
Potential energy = 2 × 9.8 × 0.5
Potential energy = 9.8 Joule
Gravitational potential energy stored is 9.8 J.
Answer:
Required diameter of hose pipe = 0.2864 mm
Solution:
From the continuity eqn, the fluid flow rate is given by:
Av = 
where
A = cross-sectional area = 
r = hose pipe radius
v = velocity of gas
Also, 
Using:
1 gallon = 3.854 l
1 mile = 1609.34 m
Therefore,
The diameter of the hose pipe = 2r = 
The diameter of the hose pipe = 
