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ValentinkaMS [17]
3 years ago
15

Does anyone know what the answers are?

Physics
1 answer:
baherus [9]3 years ago
4 0

Answer:

Option (C) is the answer

Explanation:

may be it is possible if that we stand so far

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Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass h
mestny [16]
<span>Answer: sin(incidence)/sin(refraction) = n_refraction/n_incidence sin(50) / sin(x) = 1.5 / 1 sin(50)/1.5 = sin(x) sin(x) = 0.511 x = 30.71o B] 50 degrees, same as the angle going in. You can show that by reversing the steps in A. sin(30.7)/sin(x) = 1/1.5 C] The glass is 5 cm thick. The reference angle = 30.7o Tan(30.7) = displacement / thickness Tan(30.7) = x / 5 5*sin(30.7) = x x = 2.97 cm which is the displacement.</span>
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3 years ago
Approximately how many degrees does high latitude ocean water change from the ocean surface to a depth of 1 km
saveliy_v [14]

There is no change in ocean water temperature when it is from the ocean surface to a depth of 1 km.


3 0
3 years ago
Which statement is true for a sound wave entering an area of warmer air?
Sergio [31]
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3 0
3 years ago
Read 2 more answers
You do a certain amount of work on an object initially at rest, and all the work goes into increasing the object’s speed. If you
EleoNora [17]

Answer:

\sqrt{2}v

Explanation:

The work done on the object at rest is all converted into kinetic energy, so we can write

W=\frac{1}{2}mv^2

Or, re-arranging for v,

v=\sqrt{\frac{2W}{m}}

where

v is the final speed of the object

W is the work done

m is the object's mass

If the work done on the object is doubled, we have W' = 2W. Substituting into the previous formula, we can find the new final speed of the object:

v'=\sqrt{\frac{2W'}{m}}=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2}v

So, the new speed of the object is \sqrt{2}v.

3 0
3 years ago
Please help me with this! (:
tiny-mole [99]

Answer:

(A) 18 km/h

Explanation:

4.9\frac{m}{s}=4.9\cdot \frac{\frac{1}{1000}km}{\frac{1}{3600}h}=4.9\cdot3.6\frac{km}{h}=17.64\frac{km}{h}\approx18\frac{km}{h}

8 0
3 years ago
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