Answer:
as a semicircle, a hexagon, and a rectangle
Step-by-step explanation:
The first attachment shows the decomposition according to the answer choice above. It would make area computation about as simple as it could be.
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The second attachment shows a decomposition with a circle. It leaves a very odd shape in the middle that is not easily divided into triangles, rectangles, or trapezoids.
The third attachment shows a semicircle, a pentagon, and two triangles. The pentagon is <em>not a regular pentagon</em>, so might require further decomposition in order to determine its area.
Answer:
2 4/7
Step-by-step explanation:
Answer:
The simplest form is tan(4x)
Step-by-step explanation:
* Lets revise the identity of the compound angles
- 
- 
* Lets solve the problem
- Let 9x = 5x + 4x
∴ tan(9x) = tan(5x + 4x)
- Use the rule of the compound angle
∵ 
⇒ (1)
∵ 
⇒ (2)
∵ tan(9x) = equation (2)
- Substitute (2) in (1)
∴ 
- Multiply up and down by (1 - tan(5x)tan(4x))
∴ ![\frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%285x%29%2Btan%284x%29-tan%285x%29%5B1-tan%285x%29tan%284x%29%5D%7D%7B1-tan%285x%29tan%284x%29%2Btan%285x%29%5Btan%285x%29%2Btan%284x%29%5D%7D)
- Simplify up and down
∴ 
∴ ![\frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%284x%29%2Btan%5E%7B2%7D%285x%29tan%284x%29%7D%7B%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D)
- Take tan(4x) as a common factor up
∴ ![\frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%284x%29%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D%7B%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D)
- Cancel [1 + tan²(5x)] up and down
∴ The answer is tan(4x)
Answer:
The value of P(2) is twice that of P(1).
Step-by-step explanation:
P(x) = 4x so:
P(1) = 4*1 = 4 and
P(2) = 4*2 = 8.
Answer:
-8
Step-by-step explanation:
