As an estimate we are told 5miles is 8km convert 68 km to miles ?

Mathematics

2 answers:

Alexxandr [17]2 years ago

4 0

Answer:

42.5miles

Step-by-step explanation:

68÷8= 8.5

8.5×5= 42.5 miles

we use the numbers given to us because we are finding the estimate.

our estimate is correct because 68km= 42.3 miles

Karolina [17]2 years ago

3 0

Answer:

The exact answer is 42.25 miles

Step-by-step explanation:

divide 68 by 8 and get 8.5. Multiply 8.5 by the 5 so you get 42.5. Which is a super close estimate.

You might be interested in

3 A class has 6 boys and 15 girls. What is the ratio of boys to girls?

Lubov Fominskaja [6]

Answer:

6:15

Step-by-step explanation:

Hope this helps, lemme know if you need any further help (:

7 0

2 years ago

Read 2 more answers

Which sample fairly represents the population? Check all that apply. measuring the heights of every fiftieth person on the schoo

Minchanka [31]

<span>measuring the heights of every fiftieth person on the school roster to determine the average heights of the boys in the school

wrong as should be boys only

</span><span>calling every third person on the soccer team’s roster to determine how many of the team members have completed their fundraising assignment

is the ans</span>

5 0

3 years ago

Read 2 more answers

Plz help me i'm lost badly

Annette [7]

Answer:

Im not sure but i think the answer is 0

3 0

2 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$