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erastovalidia [21]
3 years ago
15

Write the chemical equation of sodium reacts with hydrochloric acid​

Chemistry
2 answers:
BartSMP [9]3 years ago
8 0

Answer:

NaOH + HCl → H2O and NaCl.

Explanation:

plzz mark as brainliest

egoroff_w [7]3 years ago
7 0

Answer:

NaOH + HCl → H2O and NaCl.

Explanation:

I'm not sure 100%, but I think so...

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: A Ne gas sample has a pressure of 1.20 atm and volume of 35.6 L at 27.0ºC. What is the sample volume if the pressure changes t
marishachu [46]

Answer:

<em>13.84 L of Ne gas</em>

Explanation:

The exercise can be resolved by applying the General Gas Law, which establishes the relationship between the Pressure, Volume and Temperature of a gas in its initial state and its final state. Mathematically, it is:

\frac{P1 x V1}{T1} = \frac{P2 x V2}{T2}

To use this equation, you need to convert the temperatures from Celsius scale to Kelvin scale (absolute scale), and to make this conversion the formula is used:

T (K) = t (° C) + 273.15

We replace the values ​​and obtain the absolute temperatures of the initial state (T₁) and the final state (T₂)

T₁ (K) = 27.0 ° C + 273.15 = 300.15 K

T₂ (k) = 77.0 ° C + 273.15 = 350.15 K

Clearing in the equation of the general gas law V₂, and replacing the other values ​​provided by the statement, the equation and result would be:

V2 = \frac{P1 x V1 x T2}{T1 x P2} = \frac{1.20atm x 35.6L x 350.5K}{300.15K x 3.60 atm} = 13.84L

Therefore, <em>the final volume occupied by the gas sample Ne is 13.84 L</em>

3 0
3 years ago
Honors Stoichiometry Activity Worksheet
vaieri [72.5K]

Explanation: Here, we will be considering 1 cup is equal to 1 mol.

2 water + sugar + lemon juice → 4 lemonade

Moles of water present in 946.36 g of water=\frac{946.36 g}{236.59 g/mol}=4 mol

Moles of sugar present in 196.86 g of water=\frac{196.86 g}{225 g/mol}=0.8749 mol

Moles of lemon juice present in 193.37 g of water=\frac{193.37 g}{257.83 g/mol}=0.7499 mol

Moles of lemonade in 2050.25 g of water=\frac{2050.25 g}{719.42 g/mol}=2.8498 mol

As we can see that number of moles of lemon juice are limited.

So, we will consider the reaction will complete in accordance with moles of lemon juice.

1 mole lemon juice reacts with 2 mol of water,then 0.7499 mol of lemon juice will react with:

\frac{2}{1}\times 0.7499 mol = 1.4998 mol of water

Mass of water used =  1.4998 mol × 236.59 g/mol=354.8376 g

Water remained unused = 946.36 g - 354.8376 g =591.5223 g

1 mole lemon juice reacts with  mol of sugar,then 0.7499 mol of lemon juice will react with:

\frac{1}{1}\times 0.7499 mol = 0.7499 mol of water

Mass of sugar used =  0.7499 mol × 225 g/mol = 168.7275 g

Sugar remained unused = 196.86 g - 28.1325 g

1 mole of lemon juice gives 4 moles of lemonade.

Then 0.7499 mol of lemon juice will give:

\frac{4}{1}\times 0.7499 mol=2.996 mol of lemonade

Mass of lemonade obtained  = 2.996 mol × 719.42 g/mol = 2157.9722 g

Theoretical yield of lemonade = 2157.9722 g

Experimental yield of lemonade = 2050.25 g

Percentage yield of lemonade:

\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100

\frac{2050.25 g}{2157.9722 g}\times 100=95.00\%

The percentage yield of  lemonade is 95% and ingredient which remained unused were water and sugar.

6 0
4 years ago
Refer to graph of a chemical reaction. What is true of the reaction shown here?
MAXImum [283]
A would be your answer
4 0
3 years ago
Describe a method to calculate the average atomic mass of using only the atomic masses of
AnnZ [28]

Answer:

Average amu is 6.52556

Explanation:

Average the numbers

Add the two masses together.

6.01512+ 7.01600= 13.03112

Then divide by 2, we divide by 2 because that is how many #'s we are given.

13.03112/ 2= 6.52556

6 0
3 years ago
A mouse runs across a 4.56 m kitchen floor in 3.42 seconds . What is the velocity of the mouse
Lerok [7]
Velocity is the change in position divided by the time . In your problem, it should be expressed in meters per second. To solve, you must divide the distance, 4.56 meters, by the time it takes to travel that distance, which is 3.42 seconds ----->   4.56/3.42 = 1.333 meters per second is the velocity of the mouse
3 0
3 years ago
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