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sladkih [1.3K]
3 years ago
13

What is the the wavelength of light with a frequency of 230 Hz??

Chemistry
1 answer:
Andrews [41]3 years ago
3 0
Wavelength =speed/frequency
So speed/230
You need speed to get the answer
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What is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?<br><br>​
3241004551 [841]

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

<em>Where E is the energy of the photon in J, our incognite</em>

<em>h is Planck's constant = 6.6262x10⁻³⁴Js</em>

<em>And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹</em>

<em />

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon

<em />

4 0
2 years ago
Which energy transformation took place?
Goshia [24]

Answer:

C

Explanation:

The battery is chemical energy. When it is used in the flashlight, it produces light and thermal energy

PLZ MARK BRAINLIEST :)

7 0
2 years ago
Read 2 more answers
For some hypothetical metal the equilibrium number of vacancies at 750°C is 2.8 × 1024 m−3. If the density and atomic weight of
mash [69]

Answer:

The correct answer is 5.447 × 10⁻⁵ vacancies per atom.

Explanation:

Based on the given question, the at 750 degree C the number of vacancies or Nv is 2.8 × 10²⁴ m⁻³. The density of the metal is 5.60 g/cm³ or 5.60 × 10⁶ g/m³. The atomic weight of the metal given is 65.6 gram per mole. In order to determine the fraction of vacancies, the formula to be used is,  

Fv = Nv/N------ (i)  

Here Nv is the number of vacancies and N is the number of atomic sites per unit volume. To find N, the formula to be used is,  

N = NA×P/A, here NA is the Avogadro's number, which is equivalent to 6.022 × 10²³ atoms per mol, P is the density and A is the atomic weight. Now putting the values we get,  

N = 6.022 × 10²³ atoms/mol × 5.60 × 10⁶ g/m³ / 65.6 g/mol

N = 5.14073 × 10²⁸ atoms/m³

Now putting the values of Nv and N in the equation (i) we get,  

Fv = 2.8 × 10²⁴ m⁻³ / 5.14073 × 10²⁸ atoms/m^3

Fv = 5.44669 × 10⁻⁵ vacancies per atom or 5.447 × 10⁻⁵ vacancies/atom.  

4 0
2 years ago
Why do the deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer?
rodikova [14]

Answer:

The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.

Explanation:

4 0
3 years ago
When balancing a chemical equation, what are the large numbers that we adjust?
Nata [24]

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂     =>       HCl

Reactants:          Products:

2 hydrogen         1 hydrogen

2 chlorine            1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂     =>       2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

6 0
3 years ago
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