H₂O₂ + 2FeSO₄ + H₂SO₄ → Fe₂(SO₄)₃ + 2H₂O
H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O k=1
Fe²⁺ → Fe³⁺ + e⁻ k=2
H₂O₂ + 2H⁺ + 2Fe²⁺ → 2H₂O + 2Fe³⁺
Answer:
stretching and thinning of the Earth's crust occurs.
Explanation:
The result of the extension stress on Earth layers is the stretching and thinning of the Earth's crust occurs.
When there is a stress on the Earth's layers, the Earth's crust experiences the phenomena of stretching and thinning.
The mass of sodium chloride used <u>was 1.17 grams</u><u>.</u>
The mole fraction can be calculated by way of dividing the number of moles of 1 factor of an answer via the full variety of moles of all the additives of an answer. it is mentioned that the sum of the mole fraction of all the components inside the solution has to be the same as one.
mass of NaCl given = 64.9 g
mole = mass/molar mass
= 64.9 / 58.5
=<u> 1.109</u>
a mole fraction of water = 0.980
mole fraction of NaCl = 1 - 0.980
= <u>0.02</u>
1 mole of NaCl = 58.5
mass of NaCl = 58.5 × 0.02
=<u> 1.17 gram</u>
Mole Fraction describes the range of molecules contained within one aspect divided through the whole range of molecules in a given combination. it's miles quite beneficial whilst two reactive-natured components are mixed collectively.
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Answer:
The enthalpy of the solution is -35.9 kJ/mol
Explanation:
<u>Step 1:</u> Data given
Mass of lithiumchloride = 3.00 grams
Volume of water = 100 mL
Change in temperature = 6.09 °C
<u>Step 2:</u> Calculate mass of water
Mass of water = 1g/mL * 100 mL = 100 grams
<u>Step 3:</u> Calculate heat
q = m*c*ΔT
with m = the mass of water = 100 grams
with c = the heat capacity = 4.184 J/g°C
with ΔT = the chgange in temperature = 6.09 °C
q = 100 grams * 4.184 J/g°C * 6.09 °C
q =2548.1 J
<u>Step 4:</u> Calculate moles lithiumchloride
Moles LiCl = mass LiCl / Molar mass LiCl
Moles LiCl = 3 grams / 42.394 g/mol
Moles LiCl = 0.071 moles
<u>Step 5:</u> Calculate enthalpy of solution
ΔH = 2548.1 J /0.071 moles
ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)
The enthalpy of the solution is -35.9 kJ/mol