The number of orbitals that are completely full is 5.
The reason you may have thought it was 3 is because you're confusing orbitals with subshells.
In this electron configuration, the sub shells are: 1s^2, 2s^2, 2p^6, 3s^1
So, we have four sub shells.
Each sub shell consists of a specific number of orbitals. s subshells have one orbital, p subshells have three orbitals, d subshells have five orbitals, and f subshells have seven orbitals. Knowing this, we can look back at the electron configuration we were given and determine how many orbitals are filled.
1s^2 has one orbital, 2s^2 has one orbital, 2p^6 has three orbitals, and 3s^1 has one orbital. The first three subshells are completely full, so a total of five orbitals are full.
Combination of both I believe hope this helps.
Answer:
Molar mass of the unknown gas is 8.96g/mol
Explanation:
Hello,
According to Graham's law of diffusion, its states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular mass
R = k (1/√(M))
R = rate of diffusion
M = molecular mass
R₁ / R₂ = √(M₂ / M₁)
R₁ = nitrogen = 68.3s
R₂ = unknown gas = 85.6s
M₂ = molecular mass of the unknown gas
M₁ = molecular mass of nitrogen = 14g/mol
68.3 / 85.6 = (√M₂ / 14)
0.8 = (√M₂ / 14)
Take square of both sides
0.8² = M₂ / 14
M₂ = 14 × 0.64
M₂ = 8.96g/mol
The molar mass of the unknown gas is 8.96g/mol
juxtaposition best examples are Cinderella and her step-sisters or prince and the pauper.
Answer:
0.95g of Ag we can produce
Explanation:
To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:
<em>Moles AgNO₃ -Molar mass: 169.87g/mol-:</em>
1.5g * (1mol / 169.87g) = 0.0088 moles Ag
<em>Mass Ag -Molar mass: 107.87g/mol-:</em>
0.0088 moles Ag * (107.87g / mol) =
<h3>0.95g of Ag we can produce</h3>