V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
Move down c units means minus 2 from whole function
f(x) moved down 2 units means f(x)-2
so
f(x)-2=2x²-8-2
f(x)-2=2x²-10
g(x)=2x²-10
In this question the given information's should be closely noted. The
length and width of the perimeter are already given. Based on those
information's the answer to the question can be easily deduced.
Length of the rectangle = 2 1/2 inch
= 5/2 inch
Width of the rectangle = 5 1/3 inch
= 16/3 inch
Then
Perimeter of a rectangle = 2 ( Length + Width)
= 2 [(5/2) + (16/3)]
= 2 [ (45 + 32)/6]
= 2 * (77/6)
= 77/3 inch
= 25 2/3 inch
So the perimeter of the rectangle in question is 25 2/3 inch. I hope the procedure is clear to you.
